I am not able to resolve the issue that when lm(sformula) is executed, it does not show the string that is assigned to sformula. I have a feeling i
How about eval(call("lm", sformula))?
lm(sformula)
#Call:
#lm(formula = sformula)
eval(call("lm", sformula))
#Call:
#lm(formula = "y~x")
Generally speaking there is a data argument for lm. Let's do:
mydata <- data.frame(y = y, x = x)
eval(call("lm", sformula, quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)
The above call() + eval() combination can be replaced by do.call():
do.call("lm", list(formula = sformula))
#Call:
#lm(formula = "y~x")
do.call("lm", list(formula = sformula, data = quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)