Returning all maximum or minimum values that can be multiple

Question

Enumerable#max_by and Enumerable#min_by return one of the relevant elements (presumably the first one) when there are multiple max

Answer 1

arr = [1, 2, 3, 5]

arr.group_by{|a| a % 3} # => {1=>[1], 2=>[2, 5], 0=>[3]}
arr.group_by{|a| a % 3}.max.last # => [2, 5]

Answer 2

arr=[1, 2, 3, 5, 7, 8]
mods=arr.map{|e| e%3}

find max

max=mods.max
indices = []
mods.each.with_index{|m, i| indices << i if m.eql?(max)}
arr.select.with_index{|a,i| indices.include?(i)}

find min

min = mods.min
indices = []
mods.each.with_index{|m, i| indices << i if m.eql?(min)}
arr.select.with_index{|a,i| indices.include?(i)}

Sorry for clumsy code, will try to make it short.

Answer by @Sergio Tulentsev is the best and efficient answer, found things to learn there. +1

Answer 3

This is the hash equivalent of @Serio's use of group_by.

arr = [1, 2, 3, 5]

arr.each_with_object(Hash.new { |h,k| h[k] = [] }) { |e,h| h[e%3] << e }.max.last
  #=> [2, 5]

The steps:

h = arr.each_with_object(Hash.new { |h,k| h[k] = [] }) { |e,h| h[e%3] << e }
  #=> {1=>[1], 2=>[2, 5], 0=>[3]}
a = h.max
  #=> [2, [2, 5]]
a.last
  #=> [2, 5]