Get elements from list of lists

Question

is it possible to get all elements from list of lists in Prolog?

Something like: We have getElements([[[a,b,[c]],d,e],f,g,[h,[i,j]]],S) and the result is: S = [a,b,

Answer 1

You asked for all elements of a list of lists. That is, for [[1,2,3],[4]] this would be the list [1,2,3,4]. However, for [[[1],[3]]] this would be the list [[1],[3]] since [1] and [3] are elements. For this reason, flatten/2 is incorrect it gives you [1,3] as an answer. Also, for 1 it gives [1]...

Here is a solution using dcg:

seq([]) --> [].
seq([E|Es]) --> [E], seq(Es).

seqq([]) --> [].
seqq([Es|Ess]) --> seq(Es), seqq(Ess).

?- phrase(seqq([[[1],[3]]]), Xs).
Xs = [[1],[3]].

?- phrase(seqq(1), Xs).
false.

This solution now works also for cases like the following:

?- phrase(seqq([S1,S2]), [1,2]).
S1 = [],
S2 = [1,2] ;
S1 = [1],
S2 = [2] ;
S1 = [1,2],
S2 = [] ;
false.

Whereas flatten/2 is completely wrong:

?- flatten([S1,S2],[1,2]).
S1 = 1,
S2 = 2.

Answer 2

In SWI-Prolog (and maybe others), you can use flatten/2:

?- flatten([[[a,b,[c]],d,e],f,g,[h,[i,j]]], S).
S = [a, b, c, d, e, f, g, h, i|...].

Note that the SWI-Prolog manual page for flatten/2 includes the following statement:

Ending up needing flatten/3 often indicates, like append/3 for appending two lists, a bad design.

However, the page doesn't say whether there is another native predicate to replace it.

I'm sure a better answer will be supplied.