str_replace with array

Question

I\'m having some troubles with the PHP function str_replace when using arrays.

I have this message:

$message = strtolower(\"L rzzo rwldd         


        

Answer 1

Easy and better than str_replace:

<?php
$arr = array(
    "http://" => "http://www.",
    "w" => "W",
    "d" => "D");

    $word = "http://desiweb.ir";
    echo strtr($word,$arr);
?>

strtr PHP doc here

Answer 2

If the text is a simple markup and has existing anchors, stage the existing anchor tags first, swap out the urls, then replace the staged markers.

$text = '
Lorem Ipsum is simply dummy text found by searching http://google.com/?q=lorem in your <a href=https://www.mozilla.org/en-US/firefox/>Firefox</a>,
<a href="https://www.apple.com/safari/">Safari</a>, or https://www.google.com/chrome/ browser.

Link replacements will first stage existing anchor tags, replace each with a marker, then swap out the remaining links.
Links should be properly encoded.  If links are not separated from surrounding content like a trailing "." period then they it will be included in the link.
Links that are not encoded properly may create a problem, so best to use this when you know the text you are processing is not mixed HTML.

Example: http://google.com/i,m,complicate--d/index.html
Example: https://www.google.com/chrome/?123&t=123
Example: http://google.com/?q='. urlencode('<a href="http://google.com">http://google.com</a>') .'
';

// Replace existing links with a marker
$linkStore = array();
$text = preg_replace_callback('/(<a.*?a>)/', function($match) use (&$linkStore){ $key = '__linkStore'.count($linkStore).'__'; $linkStore[$key] = $match[0]; return $key; }, $text);

// Replace remaining URLs with an anchor tag
$text = preg_replace_callback("/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/", function($match) use (&$linkStore){ return '<a href="'. $match[0] .'">'. $match[0] .'</a>'; }, $text);

// Replace link markers with original
$text = str_replace(array_keys($linkStore), array_values($linkStore), $text);

echo '<pre>'.$text;

Answer 3

str_replace with arrays just performs all the replacements sequentially. Use strtr instead to do them all at once:

$new_message = strtr($message, 'lmnopq...', 'abcdef...');

Answer 4

Because str_replace() replaces left to right, it might replace a previously inserted value when doing multiple replacements.

    // Outputs F because A is replaced with B, then B is replaced with C, and so on...
    // Finally E is replaced with F, because of left to right replacements.
    $search  = array('A', 'B', 'C', 'D', 'E');
    $replace = array('B', 'C', 'D', 'E', 'F');
    $subject = 'A';
    echo str_replace($search, $replace, $subject);

Answer 5

Alternatively to the answer marked as correct, if you have to replace words instead of chars you can do it with this piece of code :

$query = "INSERT INTO my_table VALUES (?, ?, ?, ?);";
$values = Array("apple", "oranges", "mangos", "papayas");
foreach (array_fill(0, count($values), '?') as $key => $wildcard) {
    $query = substr_replace($query, '"'.$values[$key].'"', strpos($query, $wildcard), strlen($wildcard));
}
echo $query;

Demo here : http://sandbox.onlinephpfunctions.com/code/56de88aef7eece3d199d57a863974b84a7224fd7