I have a string, example:
s = \"this is a string, a\"
Where a \',\'
(comma) will always be the 3rd to the last character, aka
For deleting every ',' character in the text, you can try
s = s.split(',')
>> ["this is a string", " a"]
s = "".join(s)
>> "this is a string a"
Or in one line:
s0 = "".join(s.split(','))
A couple of variants, using the "delete the last comma" rather than "delete third last character" are:
s[::-1].replace(",","",1)[::-1]
or
''.join(s.rsplit(",", 1))
But these are pretty ugly. Slightly better is:
a, _, b = s.rpartition(",")
s = a + b
This may be the best approach if you don't know the comma's position (except for last comma in string) and effectively need a "replace from right". However Anurag's answer is more pythonic for the "delete third last character".
The best simple way is : You can use replace function as :-
>>> s = 'this is a string, a'
>>> s = s.replace(',','')
>>> s
'this is a string a'
Here, replace() function search the character ',' and replace it by '' i.e. empty character
Note that , the replace() function defaults all ',' but if you want only replace some ',' in some case you can use : s.replace(',' , '', 1)
Normally, you would just do:
s = s[:-3] + s[-2:]
The s[:-3]
gives you a string up to, but not including, the comma you want removed ("this is a string"
) and the s[-2:]
gives you another string starting one character beyond that comma (" a"
).
Then, joining the two strings together gives you what you were after ("this is a string a"
).
To slice a string of arbitrary length into multiple equal length slices of arbitrary length you could do
def slicer(string, slice_length):
return [string[i:i + slice_length]
for i in xrange(0, len(string), slice_length)]
If slice_length does not divide exactly into len(string) then there will be a single slice at the end of the list that holds the remainder.
Python strings are immutable. This means that you must create at least 1 new string in order to remove the comma, as opposed to editing the string in place in a language like C.