So here is my array.
double[] testArray = new double[10];
// will generate a random numbers from 1-20, too lazy to write the code
I want to
Generic extension method :
public static bool HasDuplicate<T>(this IEnumerable<T> source, IEqualityComparer<T> comparer)
{
if (source == null)
throw new ArgumentException(nameof(source));
HashSet<T> set = new HashSet<T>(comparer);
foreach (var item in source)
if (!set.Add(item))
return true;
return false;
}
use a hashset to add members to, then check if there a previous occurrence of current member
public bool ContainsDuplicate(double[] nums)
{
int size = nums.Length;
HashSet<double> set1 = new HashSet<double>();
for (int i = 0; i < size; i++)
{
if (set1.Contains(nums[i]))
{
return true;
}
else
{
set1.Add(nums[i]);
}
}
return false;
}
Use this:
bool CheckUniqueness(double[] values)
{
var uniqueValues = new HashSet<double>();
foreach (double d in values)
{
if(uniqueValues.Contains(d))
{
return false;
}
uniqueValues.Add(d);
}
return true;
}
We must initialize j
from i
on the first loop and add one(i+1) because we want to compare first loop value with the next value of same array.
int[] arr = new int[]{1,2,3,1,4,2,5,4};
//create one loop for arr values
for (int i = 0; i < arr.Length; i++)
{
//create nested loop for compare current values with actual value of arr
for (int j = i+1; j < arr.Length; j++)
{
//and here we put our condition
if (arr[i] == arr[j])
{
Console.WriteLine(arr[i]);
}
}
}
With (OP) 10 random doubles quite fast. The chance of a repeat: ~0.000002 %.
static bool repeat(double[] a)
{
return
a[0] == a[1] || a[0] == a[2] || a[0] == a[3] || a[0] == a[4] ||
a[0] == a[5] || a[0] == a[6] || a[0] == a[7] || a[0] == a[8] ||
a[0] == a[9] || a[1] == a[2] || a[1] == a[3] || a[1] == a[4] ||
a[1] == a[5] || a[1] == a[6] || a[1] == a[7] || a[1] == a[8] ||
a[1] == a[9] || a[2] == a[3] || a[2] == a[4] || a[2] == a[5] ||
a[2] == a[6] || a[2] == a[7] || a[2] == a[8] || a[2] == a[9] ||
a[3] == a[4] || a[3] == a[5] || a[3] == a[6] || a[3] == a[7] ||
a[3] == a[8] || a[3] == a[9] || a[4] == a[5] || a[4] == a[6] ||
a[4] == a[7] || a[4] == a[8] || a[4] == a[9] || a[5] == a[6] ||
a[5] == a[7] || a[5] == a[8] || a[5] == a[9] || a[6] == a[7] ||
a[6] == a[8] || a[6] == a[9] || a[7] == a[8] || a[7] == a[9] ||
a[8] == a[9];
}
More general, with 10 numbers ~2 times slower than above,
but ~7 times faster than the hashset approach.
static bool repeat(double[] a)
{
int k = a.Length - 1;
if (k < 70)
{
double aj;
for (int i = 0, j; i < k; )
{
for (aj = a[k--], j = k; j >= i; j--)
if (aj == a[j]) return true;
for (aj = a[i++], j = i; j <= k; j++)
if (aj == a[j]) return true;
}
return false;
}
var h = new HashSet<double>();
while (k >= 0) if (!h.Add(a[k--])) return false;
return true;
}
Two lines (slow with a repeat ;)
static bool repeat(double[] a)
{ return (new HashSet<double>(a).Count < a.Length); }
take look at my implementation its generic
and efficient
public static bool HasDuplicates<T>(IList<T> items)
{
Dictionary<T, bool> map = new Dictionary<T, bool>();
for (int i = 0; i < items.Count; i++)
{
if (map.ContainsKey(items[i]))
{
return true; // has duplicates
}
map.Add(items[i], true);
}
return false; // no duplicates
}
here are some calls
string[] strings = new[] { "1", "2", "3" };
Utility.HasDuplicates(strings)// this will return false
int[] items=new []{1,2,3,1};
Utility.HasDuplicates(items)// this will return true