python, sort descending dataframe with pandas

Question

I\'m trying to sort a dataframe by descending. I put \'False\' in the ascending argument, but my order is still ascending.

My code is:

from pandas im         


        

Answer 1

New syntax (either):

 test = df.sort_values(['one'], ascending=[False])
 test = df.sort_values(['one'], ascending=[0])

Answer 2

For pandas 0.17 and above, use this :

test = df.sort_values('one', ascending=False)

Since 'one' is a series in the pandas data frame, hence pandas will not accept the arguments in the form of a list.

Answer 3

https://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.sort_values.html

I don't think you should ever provide the False value in square brackets (ever), also the column values when they are more than one, then only they are provided as a list! Not like ['one'].

test = df.sort_values(by='one', ascending = False)

Answer 4

Edit: This is out of date, see @Merlin's answer.

[False], being a nonempty list, is not the same as False. You should write:

test = df.sort('one', ascending=False)

Answer 5

from pandas import DataFrame
import pandas as pd

d = {'one':[2,3,1,4,5],
 'two':[5,4,3,2,1],
 'letter':['a','a','b','b','c']}

df = DataFrame(d)

test = df.sort_values(['one'], ascending=False)
test