Reverse order of For Each loop

Question

One of the most powerful things about VB is ability to loop through objects in a collection WITHOUT referring to the index - for each loop.

I find it ve

Answer 1

use a second variable that is set as your wanted counter and use this one in your code

'ex: Loop from n = 19 to 16
For i = 0 To 3
   n = 19 - i
   'your code here using n as the counter
Next

Answer 2

There are other good answers but here's another alternative method of "stepping backwards" through a Range.

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Function to Invert Range into Array

This function returns a "backwards Range Array" that can be used with For..Each:

Function ReverseRange(rg As Range) As Range()
    Dim arr() As Range, r As Long, c As Long, n As Long
    With rg
        ReDim arr(1 To .Cells.Count) 'resize Range Array
        For r = .Cells(.Rows.Count, 1).Row To .Cells(1, 1).Row Step -1
            For c = .Cells(1, .Columns.Count).Column To .Cells(1, 1).Column Step -1
                n = n + 1
                Set arr(n) = .Worksheet.Cells(r, c) 'set cell in Array
            Next c
        Next r
    End With
    ReverseRange = arr  'return Range Array as function result
End Function

Example Usage:

Sub test()
    Dim oCell
    For Each oCell In ReverseRange(ActiveSheet.Range("E5:A1"))

        Debug.Print oCell.Address 'do something here with each cell

    Next oCell
End Sub

Answer 3

For built in collections (eg a Range) the short answer is: you can't. For user defined collections the answer linked by @VBlades might be useful, although the cost might outweigh the benifit.

One work around is to seperate the identification of items to be removed from the actual removal. Eg, for a range, build up a new range variable using Union, then process that variable, eg delete all the rows in one go. For the Range example, you can also take advantage of the Variant Array method to further speed things up.

Whether or not any of this is useful will depend on your actual use case.

Answer 4

It's not possible to loop backwards using the for each loop syntax.

As an alternative you can use a For i = a To 1 Step -1 loop:

Sub reverseForEach()
    Dim i As Long, rng As Range

    Set rng = ActiveSheet.Range("A1:B2")

    For i = rng.Cells.Count To 1 Step -1

        Debug.Print rng.item(i).Address
        ' Or shorthand rng(i) as the Item property 
        ' is the default property for the Range object.
        ' Prints: $B$2, $A$2, $B$1, $A$1

    Next i

End Sub

This works with all collections that have the Item property. For instance Worksheets, Areas or Shapes.

Note: The order of the loop when using on the Range object is from right to left, then up.

Answer 5

Only for Range collections. They are more complicated if they have more than 1 Area.

Basically there are two loops, the first one keeps the index of all the cells in an array and the second one creates a union of ranges from back to front

Option Explicit

Private Sub Main()
    Dim InvertedRange As Range
    Set InvertedRange = InvertRange(Application.Union(ActiveSheet.Range("A1:A2"), _
      ActiveSheet.Range("F6:F7"), ActiveSheet.Range("E4:F5"), ActiveSheet.Range("E1")))
    Dim ActualRange As Range
    For Each ActualRange In InvertedRange
        Debug.Print (ActualRange.Address(False, False) & " : " & ActualRange.Value)
    Next ActualRange
End Sub

Public Function InvertRange(ByVal rngRange_I As Range) As Range
    Dim RangesArray() As Long
    ReDim RangesArray(1 To rngRange_I.Count, 1 To rngRange_I.Count)
    Dim ActualArea As Range
    Dim ActualRange As Range
    Dim ArrayIndex As Long
    For Each ActualArea In rngRange_I.Areas
        For Each ActualRange In ActualArea
            ArrayIndex = ArrayIndex + 1
            RangesArray(ArrayIndex, 1) = ActualRange.Row
            RangesArray(ArrayIndex, 2) = ActualRange.Column
        Next ActualRange
    Next ActualArea

    Dim ActualRow As Long
    Dim ActualColumn As Long
    ActualRow = RangesArray(UBound(RangesArray, 1), 1)
    ActualColumn = RangesArray(UBound(RangesArray, 2), 2)
    With rngRange_I.Worksheet
        Dim InvertedRange As Range
        Set InvertedRange = .Cells(ActualRow, ActualColumn)
        For ArrayIndex = UBound(RangesArray, 1) To LBound(RangesArray, 1) Step -1
            ActualRow = RangesArray(ArrayIndex, 1)
            ActualColumn = RangesArray(ArrayIndex, 2)
            Set InvertedRange = Application.Union(InvertedRange, _
              .Cells(ActualRow, ActualColumn))
        Next ArrayIndex
    End With

    Set InvertRange = InvertedRange
End Function