Count number of elements that increase or decrease by a factor of 10 with recursion

前端 未结 0 615
深忆病人
深忆病人 2020-12-01 17:02
#include 

using namespace std;
int factorsOf10(int arr[], int value)
{
    int count = 0;
    int len = sizeof(arr) / sizeof(0);
    for (int i = 0;         


        
相关标签:
回答
  • 消灭零回复
提交回复
热议问题