How do you return to a sourced bash script?

后端 未结 3 2131
后悔当初
后悔当初 2020-12-01 13:40

I use "source" inside a bash script, as follows:

#!/bin/bash
source someneatscriptthatendsprematurely.sh

I would like to exit from

相关标签:
3条回答
  • 2020-12-01 14:13

    You need the return statement:

    return [n]

    Causes a function to exit with the return value specified by n. If n is omitted, the return status is that of the last command executed in the function body. If used outside a function, but during execution of a script by the . (source) command, it causes the shell to stop executing that script and return either n or the exit status of the last command executed within the script as the exit status of the script. If used outside a function and not during execution of a script by ., the return status is false. Any command associated with the RETURN trap is executed before execution resumes after the function or script.

    You can see this in action with the following two scripts:

    script1.sh:
        . script2.sh
        echo hello again
    
    script2.sh:
        echo hello
        return
        echo goodbye
    

    When you run script1.sh, you see:

    hello
    hello again
    
    0 讨论(0)
  • 2020-12-01 14:15

    I had the same problem just now

    I realized that adding a checker function and returning that will not also return the function on its caller for example.

    On bash_functions

    function install_packer_linux() {
      check_wget && check_unzip
      wget https://releases.hashicorp.com/packer/1.1.2/packer_1.1.2_linux_amd64.zip
      unzip packer_1.1.2_linux_amd64.zip
      mv packer ~/.local/bin
      rm -f packer_1.1.2_linux_amd64.zip
    }
    
    
    function check_unzip() {
      if ! [ -x "$(command -v unzip)" ]; then
        echo "Error: unzip is not installed"
        return 1
      else
        return 0
      fi
    }
    
    function check_wget() {
      if ! [ -x "$(command -v wget)" ]; then
        echo "Error!: wget is not installed"
        return 1
      else
        return 0
      fi
    }
    
    
    $ source ~/.bash_functions
    

    What happens here is since the checkers is the only place its returned so install_packer_linux will still continue

    So you can do two things here. Either keep the current format (function calling another function) as is and evaluate using truthy value then return if the values are not truthy or rewrite the checker on the main installer_packer_linux function

    Truthy:

    function install_packer_linux() {
      check_wget && check_unzip || return
      wget https://releases.hashicorp.com/packer/1.1.2/packer_1.1.2_linux_amd64.zip
      unzip packer_1.1.2_linux_amd64.zip
      mv packer ~/.local/bin
      rm -f packer_1.1.2_linux_amd64.zip
    }
    

    Notice we added || return after the checks and concatenated the checks using && so if not both checks are truthy we return the function

    0 讨论(0)
  • 2020-12-01 14:22

    Is it important that you can change environment variables? Since otherwise you can just execute the script by executing it without source:

    someneatscriptthatendsprematurely.sh
    
    0 讨论(0)
提交回复
热议问题