Find all the occurrences of a character in a string

Question

I am trying to find all the occurences of \"|\" in a string.

def findSectionOffsets(text):
    startingPos = 0
    endPos = len(text)

    for position in te         


        

Answer 1

import re
def findSectionOffsets(text)
    for i,m in enumerate(re.finditer('\|',text)) :
        print i, m.start(), m.end()

Answer 2

if you want index of all occurance of | character in a string you can do this

In [30]: import re

In [31]: str = "aaaaaa|bbbbbb|ccccc|ffffdd"

In [32]: [x.start() for x in re.finditer('\|', str)]
Out[32]: [6, 13, 19]

also you can do

In [33]: [x for x, v in enumerate(str) if v == '|']
Out[33]: [6, 13, 19]

Answer 3

The function:

def findOccurrences(s, ch):
    return [i for i, letter in enumerate(s) if letter == ch]


findOccurrences(yourString, '|')

will return a list of the indices of yourString in which the | occur.

Answer 4

It is easier to use regular expressions here;

import re

def findSectionOffsets(text):
    for m in re.finditer('\|', text):
        print m.start(0)

Answer 5

text.find() only returns the first result, and then you need to set the new starting position based on that. So like this:

def findSectionOffsets(text):
    startingPos = 0

    position = text.find("|", startingPos):
    while position > -1:
        print position
        startingPos = position + 1
        position = text.find("|", startingPos)

Answer 6

text.find returns an integer (the index at which the desired string is found), so you can run for loop over it.

I suggest:

def findSectionOffsets(text):
    indexes = []
    startposition = 0

    while True:
        i = text.find("|", startposition)
        if i == -1: break
        indexes.append(i)
        startposition = i + 1

    return indexes