How to fill OpenCV image with one solid color?
Create a new 640x480 image and fill it with purple (red+blue):
cv::Mat mat(480, 640, CV_8UC3, cv::Scalar(255,0,255));
Note:
Use numpy.full. Here's a Python that creates a gray, blue, green and red image and shows in a 2x2 grid.
import cv2
import numpy as np
gray_img = np.full((100, 100, 3), 127, np.uint8)
blue_img = np.full((100, 100, 3), 0, np.uint8)
green_img = np.full((100, 100, 3), 0, np.uint8)
red_img = np.full((100, 100, 3), 0, np.uint8)
full_layer = np.full((100, 100), 255, np.uint8)
# OpenCV goes in blue, green, red order
blue_img[:, :, 0] = full_layer
green_img[:, :, 1] = full_layer
red_img[:, :, 2] = full_layer
cv2.imshow('2x2_grid', np.vstack([
np.hstack([gray_img, blue_img]),
np.hstack([green_img, red_img])
]))
cv2.waitKey(0)
cv2.destroyWindow('2x2_grid')
Using the OpenCV C API with IplImage* img
:
Use cvSet(): cvSet(img, CV_RGB(redVal,greenVal,blueVal));
Using the OpenCV C++ API with cv::Mat img
, then use either:
cv::Mat::operator=(const Scalar& s) as in:
img = cv::Scalar(redVal,greenVal,blueVal);
or the more general, mask supporting, cv::Mat::setTo():
img.setTo(cv::Scalar(redVal,greenVal,blueVal));
For an 8-bit (CV_8U) OpenCV image, the syntax is:
Mat img(Mat(nHeight, nWidth, CV_8U);
img = cv::Scalar(50); // or the desired uint8_t value from 0-255
The simplest is using the OpenCV Mat class:
img=cv::Scalar(blue_value, green_value, red_value);
where img
was defined as a cv::Mat
.
If you are using Java for OpenCV, then you can use the following code.
Mat img = src.clone(); //Clone from the original image
img.setTo(new Scalar(255,255,255)); //This sets the whole image to white, it is R,G,B value