int object is not iterable?

Question

inp = int(input(\"Enter a number:\"))

for i in inp:
    n = n + i;
    print (n)

... throws an error: \'int\' object is not iterable<

Answer 1

try:

for i in str(inp):

That will iterate over the characters in the string representation. Once you have each character you can use it like a separate number.

Answer 2

Take your input and make sure it's a string so that it's iterable.

Then perform a list comprehension and change each value back to a number.

Now, you can do the sum of all the numbers if you want:

inp = [int(i) for i in str(input("Enter a number:"))]
print sum(inp)

Or, if you really want to see the output while it's executing:

def printadd(x,y):
    print x+y
    return x+y

inp = [int(i) for i in str(input("Enter a number:"))]
reduce(printadd,inp)

Answer 3

Side note: if you want to get the sum of all digits, you can simply do

print sum(int(digit) for digit in raw_input('Enter a number:'))

Answer 4

First, lose that call to int - you're converting a string of characters to an integer, which isn't what you want (you want to treat each character as its own number). Change:

inp = int(input("Enter a number:"))

to:

inp = input("Enter a number:")

Now that inp is a string of digits, you can loop over it, digit by digit.

Next, assign some initial value to n -- as you code stands right now, you'll get a NameError since you never initialize it. Presumably you want n = 0 before the for loop.

Next, consider the difference between a character and an integer again. You now have:

n = n + i;

which, besides the unnecessary semicolon (Python is an indentation-based syntax), is trying to sum the character i to the integer n -- that won't work! So, this becomes

n = n + int(i)

to turn character '7' into integer 7, and so forth.

Answer 5

You can try to change for i in inp: into for i in range(1,inp): Iteration doesn't work with a single int. Instead, you need provide a range for it to run.

Answer 6

for .. in statements expect you to use a type that has an iterator defined. A simple int type does not have an iterator.