What is the difference between “system32\java.exe” and “Program Files\Java\jdk1.6.0_33\bin\java.exe”?

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天涯浪人
天涯浪人 2020-12-01 09:13

I have just installed Java JDK 6u33 in Windows XP. Even though I didn\'t set the PATH environment variable, I am able to run java -version in command prompt.

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  • 2020-12-01 09:43

    (Not an answer but rather a comment on Mattias's answer) Not sure about this "dummy" business. The java.exe in system32 is a normal file, not even a symbolic or hard link. Mattias may be referring to the problem that is explained here: http://msdn.microsoft.com/en-us/library/aa384187

    In a nutshell, if you have a 64-bit system and a Java installation, 32-bit applications won't see the java.exe (nor javaw.exe, javaws.exe) that is installed in C:\Windows\System32\ because they'll be presented with C:\Windows\SysWoW64\ masquerading as C:\Windows\System32. The installer fails to put a copy of java.exe in SysWoW64, hence a 32-bit app that tries to launch Java will fail to do so. This will puzzle the user if he looks in the system32 directory using explorer, since explorer is a 64-bit app and will thus see the "real" system32 directory.

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  • 2020-12-01 09:51

    Setting the PATHvariable is just so that you can get access to javac and the other programs and tools in the jdk bin folder.

    The java.exe in \windows\system32\ is provided so that not everyone needs to set a PATH variable just to run a java program (from the command line) and selects a version (the last one installed it seems) of the installed java virtual machines (JVM) if there are more than one (publicly) installed.

    See this link for further info:

    http://mindprod.com/jgloss/javaexe.html#MULTIPLES

    Quote:

    To complicate things further the java.exe in system32 is just a dummy. It looks in the registry and then decides which real java.exe to use. The last JVM installed gets to be the one used, even if it is older. To switch JVM s, you must normally reinstall the one you want.

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