How to get a slice from “arguments”

Question

All you know that arguments is a special object that holds all the arguments passed to the function.

And as long as it is not an array - you cannot use

Answer 1

This can be a way:

var args = Array.from(arguments).slice(1);

Answer 2

You can use the method [].slice.call(arguments, 1)

[].slice will return you the slice function object and you can call it as the arguments and 1 are the parameters

Answer 3

You can "slice without slicing" by procedurally walking the arguments object:

function fun() {
  var args = [];

  for (var i = 1; i < arguments.length; i++) {
    args.push(arguments[i]);
  }

  return args;
}

fun(1, 2, 3, 4, 5); //=> [2, 3, 4, 5]

Answer 4

Q. How to slice everything but first element from arguments?

The following will return an array containing all arguments except the first:

var slicedArgs = Array.prototype.slice.call(arguments, 1);

You don't have to convert arguments to an array first, do it all in one step.

Answer 5

You can use ...rest within the function to separate the first and the rest of the arguments:

function foo(arr) {
  const [first, ...rest] = arguments;
  console.log(`first = ${first}`);
  console.log(`rest = ${rest}`);
}
//Then calling the function with 3 arguments:
foo(1,2,3)

Answer 6

Meddling with array functions is not actually necessary.

Using rest parameter syntax ...rest is cleaner and more convenient.

Example

function argumentTest(first, ...rest) {
  console.log("First arg:" + first);

  // loop through the rest of the parameters
  for (let arg of rest) {
    console.log("- " + arg);
  }
}

// call your function with any number of arguments
argumentTest("first arg", "#2", "more arguments", "this is not an argument but a contradiction");

...Rest

• See the example Fiddle
• See MDN Documentation page