Consider the following Scala code:
package scala_java
object MyScala {
def setFunc(func: Int => String) {
func(10)
}
}
Now in Ja
The easiest way for me is to defined a java interface like:
public interface JFunction<A,B> {
public B compute( A a );
}
Then modify your scala code, overloading setFunc
to accept also JFunction
objects such as:
object MyScala {
// API for scala
def setFunc(func: Int => String) {
func(10)
}
// API for java
def setFunc(jFunc: JFunction[Int,String]) {
setFunc( (i:Int) => jFunc.compute(i) )
}
}
You will naturally use the first definition from scala, but still be able to use the second one from java:
public class MyJava {
public static void main(String [] args) {
MyScala.setFunc(myFunc); // This line gives an error
}
public static final JFunction<Integer,String> myFunc =
new JFunction<Integer,String>() {
public String compute( Integer a ) {
return String.valueOf(a);
}
};
}
Here's my attempt at a solution, a little library: https://github.com/eirslett/sc8
You wrap your Java 8 lambda in F(...) and then it's converted to a Scala function.
You have to manually instantiate a Function1
in Java. Something like:
final Function1<Integer, String> f = new Function1<Integer, String>() {
public int $tag() {
return Function1$class.$tag(this);
}
public <A> Function1<A, String> compose(Function1<A, Integer> f) {
return Function1$class.compose(this, f);
}
public String apply(Integer someInt) {
return myFunc(someInt);
}
};
MyScala.setFunc(f);
This is taken from Daniel Spiewak’s “Interop Between Java and Scala” article.
In the scala.runtime
package, there are abstract classes named AbstractFunction1
and so on for other arities. To use them from Java you only need to override apply
, like this:
Function1<Integer, String> f = new AbstractFunction1<Integer, String>() {
public String apply(Integer someInt) {
return myFunc(someInt);
}
};
If you're on Java 8 and want to use Java 8 lambda syntax for this, check out https://github.com/scala/scala-java8-compat.