Store mysql query output into a shell variable

Question

I need a variable to hold results retrieved from the database. So far this is basically what I\'m trying with no success.

myvariable=$(mysql database -u $use         


        

Answer 1

If you have particular database name and a host on which you want the query to be executed then follow below query:

outputofquery=$(mysql -u"$dbusername" -p"$dbpassword" -h"$dbhostname" -e "SELECT A, B, C FROM table_a;" $dbname)

So to run the mysql queries you need to install mysql client on linux

Answer 2

You have the pipe the other way around and you need to echo the query, like this:

myvariable=$(echo "SELECT A, B, C FROM table_a" | mysql db -u $user -p $password)

Another alternative is to use only the mysql client, like this

myvariable=$(mysql db -u $user -p $password -se "SELECT A, B, C FROM table_a")

(-s is required to avoid the ASCII-art)

Now, BASH isn't the most appropriate language to handle this type of scenarios, especially handling strings and splitting SQL results and the like. You have to work a lot to get things that would be very, very simple in Perl, Python or PHP.

For example, how will you get each of A, B and C on their own variable? It's certainly doable, but if you do not understand pipes and echo (very basic shell stuff), it will not be an easy task for you to do, so if at all possible I'd use a better suited language.

Answer 3

myvariable=$(mysql database -u $user -p$password | SELECT A, B, C FROM table_a)

without the blank space after -p. Its trivial, but without don't work.

Answer 4

My two cents here:

myvariable=$(mysql database -u $user -p$password -sse "SELECT A, B, C FROM table_a" 2>&1 \
   | grep -v "Using a password")

Removes both the column names and the annoying (but necessary) password warning. Thanks @Dominic Bartl and John for this answer.

Answer 5

Other way:

Your Script:

#!/bin/sh

# Set these variables
MyUSER="root"   # DB_USERNAME
MyPASS="yourPass"   # DB_PASSWORD
MyHOST="yourHost"    # DB_HOSTNAME
DB_NAME="dbName"
CONTAINER="containerName" #if use docker

# Get data
data=$($MyHOST -u $MyUSER -p$MyPASS $DB_NAME -h $CONTAINER -e "SELECT data1,data2 from table_name LIMIT 1;"  -B --skip-column-names)

# Set data
data1=$(echo $data | awk '{print $1}')
data2=$(echo $data | awk '{print $2}')

# Print data
echo $data1 $data2

Answer 6

To read the data line-by-line into a Bash array you can do this:

while read -a row
do
    echo "..${row[0]}..${row[1]}..${row[2]}.."
done < <(echo "SELECT A, B, C FROM table_a" | mysql database -u $user -p $password)

Or into individual variables:

while read a b c
do
    echo "..${a}..${b}..${c}.."
done < <(echo "SELECT A, B, C FROM table_a" | mysql database -u $user -p $password)