Is SecureRandom
thread safe? That is, after initializing it, can access to the next random number be relied on to be thread safe? Examining the source code seem
The current implementation of SecureRandom
is thread safe, specifically the two mutating methods nextBytes(bytes[])
and setSeed(byte[])
are synchronized.
Well, as far as I've been able to tell, all mutating methods are eventually routed through those two methods, and SecureRandom
overrides a few methods in Random
to ensure that. Which works but could be brittle if the implementation is changed in the future.
The best solution is to manually synchronize on the SecureRandom
instance first. This means each call stack will acquire two locks on the same object, but that is usually very cheap on modern JVMs. That is, there is not much harm in explicitly synchronizing yourself. For example:
SecureRandom rnd = ...;
byte[] b = new byte[NRANDOM_BYTES];
synchronized (rnd) {
rnd.nextBytes(b);
}
Yes, it is. It extends Random
, which always had a de facto threadsafe implementation, and, from Java 7, explicitly guarantees threadsafety.
If many threads are using a single SecureRandom
, there might be contention that hurts performance. On the other hand, initializing a SecureRandom
instance can be relatively slow. Whether it is best to share a global RNG, or to create a new one for each thread will depend on your application. The ThreadLocalRandom class could be used as a pattern to provide a solution that supports SecureRandom
.