Let\'s suppose I have the following class:
export default class Person {
constructor(first, last) {
this.first = first;
this.last = last
I don't see how the mocked implementation actually solves anything for you. I think this makes a bit more sense
import Person from "./Person";
describe("Person", () => {
it("should...", () => {
const sayMyName = Person.prototype.sayMyName = jest.fn();
const person = new Person('guy', 'smiley');
const expected = {
first: 'guy',
last: 'smiley'
}
person.sayMyName();
expect(sayMyName).toHaveBeenCalledTimes(1);
expect(person).toEqual(expected);
});
});
Not really answer the question, but I want to show a use case where you want to mock a dependent class to verify another class.
For example: Foo
depends on Bar
. Internally Foo
created an instance of Bar
. You want to mock Bar
for testing Foo
.
Bar class
class Bar {
public runBar(): string {
return 'Real bar';
}
}
export default Bar;
Foo class
import Bar from './Bar';
class Foo {
private bar: Bar;
constructor() {
this.bar = new Bar();
}
public runFoo(): string {
return 'real foo : ' + this.bar.runBar();
}
}
export default Foo;
The test:
import Foo from './Foo';
import Bar from './Bar';
jest.mock('./Bar');
describe('Foo', () => {
it('should return correct foo', () => {
// As Bar is already mocked,
// we just need to cast it to jest.Mock (for TypeScript) and mock whatever you want
(Bar.prototype.runBar as jest.Mock).mockReturnValue('Mocked bar');
const foo = new Foo();
expect(foo.runFoo()).toBe('real foo : Mocked bar');
});
});
See also jest.requireActual(moduleName)
Using jest.spyOn() is the proper Jest way of mocking a single method and leaving the rest be. Actually there are two slightly different approaches to this.
1. Modify the method only in a single object
import Person from "./Person";
test('Modify only instance', () => {
let person = new Person('Lorem', 'Ipsum');
let spy = jest.spyOn(person, 'sayMyName').mockImplementation(() => 'Hello');
expect(person.sayMyName()).toBe("Hello");
expect(person.bla()).toBe("bla");
// unnecessary in this case, putting it here just to illustrate how to "unmock" a method
spy.mockRestore();
});
2. Modify the class itself, so that all the instances are affected
import Person from "./Person";
beforeAll(() => {
jest.spyOn(Person.prototype, 'sayMyName').mockImplementation(() => 'Hello');
});
afterAll(() => {
jest.restoreAllMocks();
});
test('Modify class', () => {
let person = new Person('Lorem', 'Ipsum');
expect(person.sayMyName()).toBe("Hello");
expect(person.bla()).toBe("bla");
});
And for the sake of completeness, this is how you'd mock a static method:
jest.spyOn(Person, 'myStaticMethod').mockImplementation(() => 'blah');
If you are using Typescript, you can do the following:
Person.prototype.sayMyName = jest.fn().mockImplementationOnce(async () =>
await 'my name is dev'
);
And in your test, you can do something like this:
const person = new Person();
const res = await person.sayMyName();
expect(res).toEqual('my name is dev');
Hope this helps someone!
Have been asking similar question and I think figured out a solution. This should work no matter where Person class instance is actually used.
const Person = require("../Person");
jest.mock("../Person", function () {
const { default: mockRealPerson } = jest.requireActual('../Person');
mockRealPerson.prototype.sayMyName = function () {
return "Hello";
}
return mockRealPerson
});
test('MyTest', () => {
const person = new Person();
expect(person.sayMyName()).toBe("Hello");
expect(person.bla()).toBe("bla");
});
rather than mocking the class you could extend it like this:
class MockedPerson extends Person {
sayMyName () {
return 'Hello'
}
}
// and then
let person = new MockedPerson();