Converting integer to digit list

Question

What is the quickest and cleanest way to convert an integer into a list?

For example, change 132 into [1,3,2] an

Answer 1

>>>list(map(int, str(number)))  #number is a given integer

It returns a list of all digits of number.

Answer 2

By looping it can be done the following way :)

num1= int(input('Enter the number'))
sum1 = num1 #making a alt int to store the value of the orginal so it wont be affected
y = [] #making a list 
while True:
    if(sum1==0):#checking if the number is not zero so it can break if it is
        break
    d = sum1%10 #last number of your integer is saved in d
    sum1 = int(sum1/10) #integer is now with out the last number ie.4320/10 become 432
    y.append(d) # appending the last number in the first place

y.reverse()#as last is in first , reversing the number to orginal form
print(y)

Answer becomes

Enter the number2342
[2, 3, 4, 2]

Answer 3

The shortest and best way is already answered, but the first thing I thought of was the mathematical way, so here it is:

def intlist(n):
    q = n
    ret = []
    while q != 0:
        q, r = divmod(q, 10) # Divide by 10, see the remainder
        ret.insert(0, r) # The remainder is the first to the right digit
    return ret

print intlist(3)
print '-'
print intlist(10)
print '--'
print intlist(137)

It's just another interesting approach, you definitely don't have to use such a thing in practical use cases.

Answer 4

you can use:

First convert the value in a string to iterate it, Them each value can be convert to a Integer value = 12345

l = [ int(item) for item in str(value) ]