How do I modify serialized form data in jQuery?

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你的背包
你的背包 2020-11-30 23:14

I am trying to submit my form in AJAX, so I have to serialize() the data. But I am using fckEditor and jQuery doesn\'t know how to deal with it, so after the se

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  • 2020-12-01 00:04

    Here is a full jquery plugin based on @T.J's answer. You can call

    $('form#myForm').awesomeFormSerializer({
        foo: 'bar',
    })
    

    Which will replace or add the param 'foo' with value 'bar' (or any other param you add in the object)

    jQuery plugin :

    // Not builtin http://stackoverflow.com/a/5075798/2832282
    (function ( $ ) {
        // Pass an object of key/vals to override
        $.fn.awesomeFormSerializer = function(overrides) {
            // Get the parameters as an array
            var newParams = this.serializeArray();
    
            for(var key in overrides) {
                var newVal = overrides[key]
                // Find and replace `content` if there
                for (index = 0; index < newParams.length; ++index) {
                    if (newParams[index].name == key) {
                        newParams[index].value = newVal;
                        break;
                    }
                }
    
                // Add it if it wasn't there
                if (index >= newParams.length) {
                    newParams.push({
                        name: key,
                        value: newVal
                    });
                }
            }
    
            // Convert to URL-encoded string
            return $.param(newParams);
        }
    }( jQuery ));
    
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  • 2020-12-01 00:07

    use the following function it worked for me

    function(elementName,newVal)
    {
        var postData = $("#formID").serialize();
    
    var res = postData.split("&");
    var str = "";
    
    for(i=0;i<res.length;i++)
      {
        if(elementName == res[i].split("=")[0])
          {
            str += elementName + "=" + newVal+ "&";
          }
          else
          {
            str += res[i] + "&";
          }
      }
    return str;
    }
    
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  • 2020-12-01 00:10

    serialize returns a URL-encoded string containing the form fields. If you need to append to it, you do so using the standard URL-encoded string rules, e.g.:

    var values = $("#frmblog").serialize();
    values += "&content=" + encodeURIComponent(content_val);
    

    (The above assumes there will always be one value in values after the serialize call; if that's not necessarily true, determine whether to use & based on whether values is empty before you add to it.)

    Alternately, if you like, you can use serializeArray and then add to the array and use jQuery.param to turn the result into a query string, but that seems a long way 'round:

    // You can also do this, but it seems a long way 'round
    var values = $("#frmblog").serializeArray();
    values.push({
        name: "content",
        value: content_val
    });
    values = jQuery.param(values);
    

    Update: In a comment added later you said:

    The problem is, there is some default values being set in the 'content' key during the serilization process, so I can't just attach a new value, I have to update the one already in it"

    That changes things. It's a pain to look for content within the URL-encoded string, so I'd go with the array:

    var values, index;
    
    // Get the parameters as an array
    values = $("#frmblog").serializeArray();
    
    // Find and replace `content` if there
    for (index = 0; index < values.length; ++index) {
        if (values[index].name == "content") {
            values[index].value = content_val;
            break;
        }
    }
    
    // Add it if it wasn't there
    if (index >= values.length) {
        values.push({
            name: "content",
            value: content_val
        });
    }
    
    // Convert to URL-encoded string
    values = jQuery.param(values);
    

    You'd probably want to make this a reusable function.

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  • 2020-12-01 00:13

    With ES15 now. You can use this instead one for editing current submitted value (the shortest one)

    var values = $("#frmblog").serializeArray();
    values.find(input => input.name == 'content').value = content_val;
    console.log(values);
    

    or native function

    var values = $("#frmblog").serializeArray();
    values.find(function(input) { 
        return input.name == 'content';
    }).value = content_val;
    console.log(values);
    
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