Use of exit() function

Question

I want to know how and when can I use the exit() function like the program in my book:

#include

void main()
{
    int goals;
            


        

Answer 1

Try using exit(0); instead. The exit function expects an integer parameter. And don't forget to #include <stdlib.h>.

Answer 2

You must add a line with #include <stdlib.h> to include that header file and exit must return a value so assign some integer in exit(any_integer).

Answer 3

exit(int code); is declared in stdlib.h so you need an

#include <stdlib.h>

Also:
- You have no parameter for the exit(), it requires an int so provide one.
- Burn this book, it uses goto which is (for everyone but linux kernel hackers) bad, very, very, VERY bad.

Edit:
Oh, and

void main()

is bad, too, it's:

int main(int argc, char *argv[])

Answer 4

The exit() function is a type of function with a return type without an argument. It's defined by the stdlib header file.

You need to use ( exit(0) or exit(EXIT_SUCCESS)) or (exit(non-zero) or exit(EXIT_FAILURE) ).

Answer 5

Include stdlib.h in your header, and then call abort(); in any place you want to exit your program. Like this:

switch(varName)
{
    case 1: 
     blah blah;
    case 2:
     blah blah;
    case 3:
     abort();
}

When the user enters the switch accepts this and give it to the case 3 where you call the abort function. It will exit your screen immediately after hitting enter key.

Answer 6

Try man exit.

---

Oh, and:

#include <stdlib.h>

int main(void) {
  /*  ...  */
  if (error_occured) {
    return (EXIT_FAILURE);
  }
  /*  ...  */
  return (EXIT_SUCCESS);
}