Spring Security Login Page

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被撕碎了的回忆 2020-11-30 22:45

I developed an application that uses Spring Security\'s default login page. However I want to implement my own login page. I will put a login.html instead of a jsp page. I w

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  • 2020-11-30 23:07

    There are four requirements for a custom login page in Spring Security:

    1. There is an input field named j_username which will contain the name used for the authentication credentials.
    2. There is an input field named j_password which will contain the password used for the authentication credentials.
    3. The url to which these values are POSTed matches the url defined in the login-processing-url attribute of the form-login element in your Spring Security configuration.
    4. The location of the custom login form must be specified in the login-page attribute of the form-login element in your Spring Security configuration.

    Login.html

        <body>
          <form action="/j_spring_security_check" method="POST">
            <label for="username">User Name:</label>
            <input id="username" name="j_username" type="text"/>
            <label for="password">Password:</label>
            <input id="password" name="j_password" type="password"/>
            <input type="submit" value="Log In"/>
          </form>
        </body>
    

    Spring Security Configuration File

        <http use-expressions="true">
          <intercept-url pattern="/login*" access="isAnonymous()"/>
          <intercept-url pattern="/**" access="isFullyAuthenticated()"/>
          <form-login
            login-page="/login.html"
            login-processing-url="/j_spring_security_check.action"
            authentication-failure-url="/login_error.html"
            default-target-url="/home.html"
            always-use-default-target="true"/>
        </http>
    
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  • 2020-11-30 23:27

    I have been working for a couple of days on implementing spring security in my project and the configuration that finally did it was the following:

    spring-security.xml

    <security:http auto-config="true" disable-url-rewriting="true" use-expressions="true">
    
        <security:form-login 
            login-page="/login.html"
            login-processing-url="/j_spring_security_check.action"
            default-target-url="/index.html"
            always-use-default-target="true"
            authentication-failure-url="/login.html?error=true" />
        <security:intercept-url pattern="/login*" access="isAnonymous()" />
        <security:intercept-url pattern="/**" access="hasRole('ROLE_USER')" />
    </security:http>
    
    <security:authentication-manager>
        <security:authentication-provider>
            <security:jdbc-user-service
                data-source-ref="dataSource"
                users-by-username-query="select username, password, enabled from smartcaldb.users where username=?"
                authorities-by-username-query="select u.username, r.authority from smartcaldb.users u, smartcaldb.roles r where u.userid = r.userid and u.username =?" />
        </security:authentication-provider>
    </security:authentication-manager>
    

    spring-config.xml

    <mvc:annotation-driven />
    <context:component-scan base-package="com.smartcal.**" />
    
    <!-- setup database connectivity bean -->
    
    <bean id="dataSource" class="org.apache.commons.dbcp2.BasicDataSource"
        destroy-method="close">
        <property name="driverClassName" value="${jdbc.driverClassName}" />
        <property name="url" value="${jdbc.url}" />
        <property name="username" value="${jdbc.username}" />
        <property name="password" value="${jdbc.password}" />
    </bean>
    
    <context:property-placeholder location="/WEB-INF/jdbc.properties" />
    
    <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate">
        <constructor-arg ref="dataSource"/>
    </bean>
    

    web.xml

    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
    </welcome-file-list>
    
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/spring-config.xml
            /WEB-INF/spring-security.xml
        </param-value>
    </context-param>
    
    <listener>
        <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
    </listener>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    
    <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/login</url-pattern>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
    
    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
        <init-param>
            <param-name>contextAttribute</param-name>
            <param-value>org.springframework.web.context.WebApplicationContext.ROOT</param-value>
        </init-param>
    </filter>
    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
    
    <error-page>
        <error-code>403</error-code>
        <location>/403</location>
    </error-page>
    

    login.html

    <body>
        <form action="/smartcal/j_spring_security_check.action" method="POST">
            <label for="username">User Name:</label>
            <input id="username" name="j_username" type="text" />
            <label for="password">Password:</label>
            <input id="password" name="j_password" type="password" />
            <input type="submit" value="Log In" />
        </form>
    </body>
    

    for logout use url - "/{yourAppPathInTheContainer}/j_spring_security_logout"

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