Get characters after last / in url

Question

I want to get the characters after the last / in an url like http://www.vimeo.com/1234567

How do I do with php?

Answer 1

Very simply:

$id = substr($url, strrpos($url, '/') + 1);

strrpos gets the position of the last occurrence of the slash; substr returns everything after that position.

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As mentioned by redanimalwar if there is no slash this doesn't work correctly since strrpos returns false. Here's a more robust version:

$pos = strrpos($url, '/');
$id = $pos === false ? $url : substr($url, $pos + 1);

Answer 2

$str = basename($url);

Answer 3

array_pop(explode("/", "http://vimeo.com/1234567")); will return the last element of the example url

Answer 4

$str = "http://www.vimeo.com/1234567";
$s = explode("/",$str);
print end($s);

Answer 5

You could explode based on "/", and return the last entry:

print end( explode( "/", "http://www.vimeo.com/1234567" ) );

That's based on blowing the string apart, something that isn't necessary if you know the pattern of the string itself will not soon be changing. You could, alternatively, use a regular expression to locate that value at the end of the string:

$url = "http://www.vimeo.com/1234567";

if ( preg_match( "/\d+$/", $url, $matches ) ) {
    print $matches[0];
}

Answer 6

Two one liners - I suspect the first one is faster but second one is prettier and unlike end() and array_pop(), you can pass the result of a function directly to current() without generating any notice or warning since it doesn't move the pointer or alter the array.

$var = 'http://www.vimeo.com/1234567';

// VERSION 1 - one liner simmilar to DisgruntledGoat's answer above
echo substr($a,(strrpos($var,'/') !== false ? strrpos($var,'/') + 1 : 0));

// VERSION 2 - explode, reverse the array, get the first index.
echo current(array_reverse(explode('/',$var)));