How to check if a file is empty in Bash?

Question

I have a file called diff.txt. I Want to check whether it is empty.

I wrote a bash script something like below, but I couldn\'t get it work.

Answer 1

While the other answers are correct, using the "-s" option will also show the file is empty even if the file does not exist.
By adding this additional check "-f" to see if the file exists first, we ensure the result is correct.

if [ -f diff.txt ]
then
  if [ -s diff.txt ]
  then
    rm -f empty.txt
    touch full.txt
  else
    rm -f full.txt
    touch empty.txt
  fi
else
  echo "File diff.txt does not exist"
fi

Answer 2

Many of the answers are correct but I feel like they could be more complete / simplistic etc. for example :

Example 1 : Basic if statement

# BASH4+ example on Linux :

typeset read_file="/tmp/some-file.txt"
if [ ! -s "${read_file}" ]  || [ ! -f "${read_file}" ] ;then
    echo "Error: file (${read_file}) not found.. "
    exit 7
fi

if $read_file is empty or not there stop the show with exit. More than once I have had misread the top answer here to mean the opposite.

Example 2 : As a function

# -- Check if file is missing /or empty --
# Globals: None
# Arguments: file name
# Returns: Bool
# --
is_file_empty_or_missing() {
    [[ ! -f "${1}" || ! -s "${1}" ]] && return 0 || return 1
}

Answer 3

[ -s file.name ] || echo "file is empty"

Answer 4

@geedoubleya answer is my favorite.

However, I do prefer this

if [[ -f diff.txt && -s diff.txt ]]
then
  rm -f empty.txt
  touch full.txt
elif [[ -f diff.txt && ! -s diff.txt ]]
then
  rm -f full.txt
  touch empty.txt
else
  echo "File diff.txt does not exist"
fi