How to convert XML to JSON in Python? [duplicate]

Answer 1

Jacob Smullyan wrote a utility called pesterfish which uses effbot's ElementTree to convert XML to JSON.

Answer 2

xmltodict (full disclosure: I wrote it) can help you convert your XML to a dict+list+string structure, following this "standard". It is Expat-based, so it's very fast and doesn't need to load the whole XML tree in memory.

Once you have that data structure, you can serialize it to JSON:

import xmltodict, json

o = xmltodict.parse('<e> <a>text</a> <a>text</a> </e>')
json.dumps(o) # '{"e": {"a": ["text", "text"]}}'

Answer 3

Soviut's advice for lxml objectify is good. With a specially subclassed simplejson, you can turn an lxml objectify result into json.

import simplejson as json
import lxml

class objectJSONEncoder(json.JSONEncoder):
  """A specialized JSON encoder that can handle simple lxml objectify types
      >>> from lxml import objectify
      >>> obj = objectify.fromstring("<Book><price>1.50</price><author>W. Shakespeare</author></Book>")       
      >>> objectJSONEncoder().encode(obj)
      '{"price": 1.5, "author": "W. Shakespeare"}'       
 """


    def default(self,o):
        if isinstance(o, lxml.objectify.IntElement):
            return int(o)
        if isinstance(o, lxml.objectify.NumberElement) or isinstance(o, lxml.objectify.FloatElement):
            return float(o)
        if isinstance(o, lxml.objectify.ObjectifiedDataElement):
            return str(o)
        if hasattr(o, '__dict__'):
            #For objects with a __dict__, return the encoding of the __dict__
            return o.__dict__
        return json.JSONEncoder.default(self, o)

See the docstring for example of usage, essentially you pass the result of lxml objectify to the encode method of an instance of objectJSONEncoder

Note that Koen's point is very valid here, the solution above only works for simply nested xml and doesn't include the name of root elements. This could be fixed.

I've included this class in a gist here: http://gist.github.com/345559

Answer 4

One possibility would be to use Objectify or ElementTree from the lxml module. An older version ElementTree is also available in the python xml.etree module as well. Either of these will get your xml converted to Python objects which you can then use simplejson to serialize the object to JSON.

While this may seem like a painful intermediate step, it starts making more sense when you're dealing with both XML and normal Python objects.

Answer 5

In general, you want to go from XML to regular objects of your language (since there are usually reasonable tools to do this, and it's the harder conversion). And then from Plain Old Object produce JSON -- there are tools for this, too, and it's a quite simple serialization (since JSON is "Object Notation", natural fit for serializing objects). I assume Python has its set of tools.

Answer 6

I wrote a small command-line based Python script based on pesterfesh that does exactly this:

https://github.com/hay/xml2json