PHP- Decode JSON

Question

I have the following script to get search results from an API and then slice the array and dump it, I am having trouble decoding the JSON into an array, it returns Arr

Answer 1

Separate your php from html please, use indentation and:

$array = json_decode($data, TRUE); //second param used for associative array return

Example #1 json_decode() examples
<?php
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

var_dump(json_decode($json));
var_dump(json_decode($json, true));

?>
The above example will output:
object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

array(5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

P.S: From the Bible (http://php.net/manual/en/function.json-decode.php)

Answer 2

Try json_decode

$array = json_decode($data, true);

Then you'll get an array instead of an object.

Example #1 json_decode() examples

<?php
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';

var_dump(json_decode($json));
var_dump(json_decode($json, true));

?>

The above example will output:

object(stdClass)#1 (5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

array(5) {
    ["a"] => int(1)
    ["b"] => int(2)
    ["c"] => int(3)
    ["d"] => int(4)
    ["e"] => int(5)
}

Answer 3

If input is in array format then also you can use the same function json_decode. You just need to apply loop for result.

json = '{

"a1":{ "field1":"name1", "field2":age1, "field3":"country1" },

"a2":{ "field1":"name2", "field2":age2, "field3":"country2" },

"a3":{ "field1":"name3", "field2":age3, "field3":"country3" } }';

$Array = json_decode($json, true);

foreach ($Array as $key => $value)
{

    echo " $key ";

    foreach ($value as $k => $val)    
    {
        echo "$k | $val <br />";
    } 

}