NSString to NSArray

Question

I want to split an NSString into an NSArray. For example, given:

NSString *myString=@\"ABCDEF\";

I want an

Answer 1

NSMutableArray *chars = [[NSMutableArray alloc] initWithCapacity:[theString length]];
for (int i=0; i < [theString length]; i++) {
    NSString *ichar  = [NSString stringWithFormat:@"%C", [theString characterAtIndex:i]];
    [chars addObject:ichar];
}

Answer 2

Without loop you can use this:

NSString *myString = @"ABCDEF";
NSMutableString *tempStr =[[NSMutableString alloc] initWithString:myString];

if([myString length] != 0)
{
    NSError  *error  = NULL;

    // declare regular expression object
    NSRegularExpression *regex =[NSRegularExpression regularExpressionWithPattern:@"(.)" options:NSMatchingReportCompletion error:&error];

    // replace each match with matches character + <space> e.g. 'A' with 'A '
    [regex replaceMatchesInString:tempStr options:NSMatchingReportCompletion range:NSMakeRange(0,[myString length]) withTemplate:@"$0 "];

    // trim last <space> character
    [tempStr replaceCharactersInRange:NSMakeRange([tempStr length] - 1, 1) withString:@""];

    // split into array
    NSArray * arr = [tempStr componentsSeparatedByString:@" "];

    // print
    NSLog(@"%@",arr);
}

This solution append space in front of each character with the help of regular expression and uses componentsSeparatedByString with <space> to return an array

Answer 3

NSMutableArray *letterArray = [NSMutableArray array];
NSString *letters = @"ABCDEF                                                                    

                                                        
            

Answer 4

Swift 4.2:

String to Array

let list = "Karin, Carrie, David"

let listItems = list.components(separatedBy: ", ")

Output : ["Karin", "Carrie", "David"]

Array to String

let list = ["Karin", "Carrie", "David"]

let listStr = list.joined(separator: ", ")

Output : "Karin, Carrie, David"

Answer 5

This link contains examples to split a string into a array based on sub strings and also based on strings in a character set. I hope that post may help you.

here is the code snip

NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
    NSString *ichar  = [NSString stringWithFormat:@"%c", [myString characterAtIndex:i]];
    [characters addObject:ichar];
}

Answer 6

In Swift, this becomes very simple.

Swift 3:

myString.characters.map { String($0) }

Swift 4:

myString.map { String($0) }