C++ Literal String Concatenation [duplicate]

Answer 1

This is build into C++:

#include <iostream>
#include <string>

int main()
{
    std::string s("Stand back! I've got jimmies!" "DDD");
    std::cout << "Stand back! I've got jimmies!" "DDD";
}

output:

Stand back! I've got jimmies!DDD

Answer 2

"ab" is a const char *. 'c' is a char. My guess is that 'c' is converted to an integer, said integer is added to the address of "ab", and the resulting pointer is passed to std::string's constructor. You're lucky it's not miserably crashing.

See the other answers for how to do the concatenation properly.