python matrix transpose and zip

Question

How to get the transpose of this matrix..Any easier ,algorithmic way to do this...

1st question:

 Input  a=[[1,2,3],[4,5,6],[7,8,9]]
 Expected outpu         


        

Answer 1

You can use list(zip(*a)).

By using *a, your list of lists can have any number of entries.

Answer 2

You can use numpy.transpose

numpy.transpose

>>> import numpy
>>> a = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
>>> numpy.transpose(a)
array([[1, 4, 7],
       [2, 5, 8],
       [3, 6, 9]])

Answer 3

Try this replacing appropriate variable

import numpy as np

data = ((0, 1, 2), (3, 4, 5), (6, 7, 8), (9, 10, 11))

data_transpose = np.transpose(data) # replace with your code
print(data_transpose)

Answer 4

Use zip(*a):

>>> zip(*a)
[(1, 4, 7), (2, 5, 8), (3, 6, 9)]

How it works: zip(*a) is equal to zip(a[0], a[1], a[2]).

Answer 5

Solution is to use tuple() function.

Here is an example how to do that in your case :

a      = [[1,2,3],[4,5,6],[7,8,9]]
output = tuple(zip(*a))

print(output)

Answer 6

question answers:

>>> import numpy as np
>>> first_answer = np.transpose(a)
>>> second_answer = [list(i) for i in zip(*a)]

thanks to afg for helping out