play .wav file from jar as resource using java

Question

I want to play a .wav file using java code which is in a jar file as resource. My code is look like this -

try {
     URL defaultSound = getClass().getResou         


        

Answer 1

like Kal wrote :

1. InputStream is = getClass().getResourceAsStream("......");
2. AudioInputStream ais = AudioSystem.getAudioInputStream(is);...

I did just that and it didn't work at first but the problem of "java.io.IOException" was that I used File.separator and for some reason win 8.1 couldn't handle "\\"...

public AudioInputStream getSound(String fileName){
    InputStream inputSound;
    AudioInputStream audioInStr;
    String fs = File.separator;

    try {
       absolutePath = fs +packageName+ fs +folderName+ fs +fileName;
       inputSound = getClass().getResourceAsStream(absolutePath);

       //if null pointer exception try unix, for some reason \\ doesn't work on win 8.1
       if(inputSound == null) {
           absolutePath = "/" + packageName + "/" + folderName + "/" + fileName;
           inputSound = getClass().getResourceAsStream(absolutePath);
       }

       audioInStr = AudioSystem.getAudioInputStream(new BufferedInputStream(inputSound));
       return audioInStr;
    }

Answer 2

Change:

AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(soundFile);

To:

System.out.println("defaultSound " + defaultSound);  // check the URL!
AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(defaultSound);

Answer 3

this worked fine for me:

public void playSound() {
        InputStream in;
        try {
            in = new BufferedInputStream(new FileInputStream(new File(
                    getClass().getClassLoader()
                            .getResource("com/kaito/resources/sound.wav").getPath())));
            AudioStream audioStream = new AudioStream(in);
            AudioPlayer.player.start(audioStream);
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }