I need to create a string of hex digits from a list of random integers (0-255). Each hex digit should be represented by two characters: 5 - \"05\", 16 - \"10\", etc.
Example with some beautifying, similar to the sep option available in python 3.8
def prettyhex(nums, sep=''):
return sep.join(f'{a:02x}' for a in nums)
numbers = [0, 1, 2, 3, 127, 200, 255]
print(prettyhex(numbers,'-'))
output
00-01-02-03-7f-c8-ff
With python 2.X, you can do the following:
numbers = [0, 1, 2, 3, 127, 200, 255]
print "".join(chr(i).encode('hex') for i in numbers)
'000102037fc8ff'
From Python documentation. Using the built in format() function you can specify hexadecimal base using an 'x' or 'X' Example:
x= 255 print('the number is {:x}'.format(x))
Output:
the number is ff
Here are the base options
Type
'b' Binary format. Outputs the number in base 2.
'c' Character. Converts the integer to the corresponding unicode character before printing.
'd' Decimal Integer. Outputs the number in base 10.
'o' Octal format. Outputs the number in base 8.
'x' Hex format. Outputs the number in base 16, using lower- case letters for the digits above 9.
'X' Hex format. Outputs the number in base 16, using upper- case letters for the digits above 9.
'n' Number. This is the same as 'd', except that it uses the current locale setting to insert the appropriate number separator characters.
None The same as 'd'.
Python 2:
>>> str(bytearray([0,1,2,3,127,200,255])).encode('hex')
'000102037fc8ff'
Python 3:
>>> bytearray([0,1,2,3,127,200,255]).hex()
'000102037fc8ff'
''.join('%02x'%i for i in input)
Yet another option is binascii.hexlify
:
a = [0,1,2,3,127,200,255]
print binascii.hexlify(bytes(bytearray(a)))
prints
000102037fc8ff
This is also the fastest version for large strings on my machine.
In Python 2.7 or above, you could improve this even more by using
binascii.hexlify(memoryview(bytearray(a)))
saving the copy created by the bytes
call.