SQL: how to select a single id (“row”) that meets multiple criteria from a single column

Question

I have a very narrow table: user_id, ancestry.

The user_id column is self explanatory.

The ancestry column contains the country from where the user\'s ancest

Answer 1

like the answer above but I have a duplicate record so I have to create a subquery with distinct

Select user_id
(
   select distinct userid
   from yourtable
   where user_id = @userid

) t1
where 
ancestry in ('England', 'France', 'Germany')
group by user_id
having count(user_id) = 3

this is what I used because I have multiple record(download logs) and this checks that all the required files have been downloaded

Answer 2

SELECT DISTINCT (user_id) 
FROM [user]
WHERE user.user_id In (select user_id from user where ancestry = 'England') 
    And user.user_id In (select user_id from user where ancestry = 'France') 
    And user.user_id In (select user_id from user where ancestry = 'Germany');`

Answer 3

Users who have one of the 3 countries

SELECT DISTINCT user_id
FROM table
WHERE ancestry IN('England','France','Germany')

Users who have all 3 countries

SELECT DISTINCT A.userID
FROM table A
   INNER JOIN table B on A.user_id = B.user_id
   INNER JOIN table C on A.user_id = C.user_id
WHERE A.ancestry = 'England'
   AND B.ancestry = 'Germany'
   AND C.ancestry = 'France'

Answer 4

First way: JOIN:

get people with multiple countries:

SELECT u1.user_id 
FROM users u1
JOIN users u2
on u1.user_id  = u2.user_id 
AND u1.ancestry <> u2.ancestry

Get people from 2 specific countries:

SELECT u1.user_id 
FROM users u1
JOIN users u2
on u1.user_id  = u2.user_id 
WHERE u1.ancestry = 'Germany'
AND u2.ancestry = 'France'

For 3 countries... join three times. To only get the result(s) once, distinct.

Second way: GROUP BY

This will get users which have 3 lines (having...count) and then you specify which lines are permitted. Note that if you don't have a UNIQUE KEY on (user_id, ancestry), a user with 'id, england' that appears 3 times will also match... so it depends on your table structure and/or data.

SELECT user_id 
FROM users u1
WHERE ancestry = 'Germany'
OR ancestry = 'France'
OR ancestry = 'England'
GROUP BY user_id
HAVING count(DISTINCT ancestry) = 3

Answer 5

brute force (and only tested on an Oracle system, but I think this is pretty standard):

select distinct usr_id from users where user_id in (
    select user_id from (
      Select user_id, Count(User_Id) As Cc
      From users 
      GROUP BY user_id
    ) Where Cc =3
  )
  and ancestry in ('England', 'France', 'Germany')
;

edit: I like @HuckIt's answer even better.

Answer 6

Try this:

Select user_id
from yourtable
where ancestry in ('England', 'France', 'Germany')
group by user_id
having count(user_id) = 3

The last line means the user's ancestry has all 3 countries.