How to slice a Pandas Data Frame by position?

Question

I have a Pandas Data Frame object that has 1000 rows and 10 columns. I would simply like to slice the Data Frame and take the first 10 rows. How can I do this? I\'ve been tr

Answer 1

You can also do as a convenience:

df[:10]

Answer 2

dataframe[:n] - Will return first n-1 rows

Answer 3

http://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.head.html?highlight=head#pandas.DataFrame.head

df2 = df.head(10)

should do the trick

Answer 4

df.ix[10,:] gives you all the columns from the 10th row. In your case you want everything up to the 10th row which is df.ix[:9,:]. Note that the right end of the slice range is inclusive: http://pandas.sourceforge.net/gotchas.html#endpoints-are-inclusive

Answer 5

I can see at least three options:

1.

df[:10]

2. Using head

df.head(10)

For negative values of n, this function returns all rows except the last n rows, equivalent to df[:-n] [Source].

3. Using iloc

df.iloc[:10]