Removing trailing zeros from BigDecimal in Java

Question

I need to remove trailing zeros from BigDecimal along with RoundingMode.HALF_UP. For instance,

Value        Output

15.3456  <=&         


        

Answer 1

You can also accomplish this with String.format(), like so:

final BigDecimal b = new BigDecimal("600.0").setScale(2, RoundingMode.HALF_UP);
String f = String.format("%.0f", b);
System.out.println(f); //600

Answer 2

If you want to do this at your BigDecimal object and not convert it into a String with a formatter you can do it on Java 8 with 2 steps:

1. stripTrailingZeros()
2. if scale < 0 setScale to 0 if don't like esponential/scientific notation

You can try this snippet to better understand the behaviour

BigDecimal bigDecimal = BigDecimal.valueOf(Double.parseDouble("50"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
if (bigDecimal.scale()<0)
    bigDecimal= bigDecimal.setScale(0);
System.out.println(bigDecimal);//50
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50.20"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
if (bigDecimal.scale()<0)
    bigDecimal= bigDecimal.setScale(0);
System.out.println(bigDecimal);//50.2
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
System.out.println(bigDecimal);//5E+1
bigDecimal = BigDecimal.valueOf(Double.parseDouble("50.20"));
bigDecimal = bigDecimal.setScale(2);
bigDecimal = bigDecimal.stripTrailingZeros();
System.out.println(bigDecimal);//50.2

Answer 3

Note that stripTrailingZeros() doesn't do very well either.

On this:

val = new BigDecimal("0.0000").stripTrailingZeros();
System.out.println(val + ": plain=" + val.toPlainString());

val = new BigDecimal("40.0000").stripTrailingZeros();
System.out.println(val + ": plain=" + val.toPlainString());

val = new BigDecimal("40.50000").stripTrailingZeros();
System.out.println(val + ": plain=" + val.toPlainString());

Output (Java 7):

0.0000: plain=0.0000
4E+1: plain=40
40.5: plain=40.5

Output (Java 8):

0: plain=0
4E+1: plain=40
40.5: plain=40.5

The 0.0000 issue in Java 7 is fixed in Java 8 by the following java fix.

Answer 4

You should make some calculation on the BigDecimal, and then round it half up e.g.

    BigDecimal toPay = new BigDecimal(1453.00005);
    toPay = toPay.multiply(new BigDecimal(1)).setScale(2, RoundingMode.HALF_UP)

It worked for me.

Answer 5

Use toPlainString()

BigDecimal d = new BigDecimal("600.0").setScale(2, RoundingMode.HALF_UP).stripTrailingZeros();
System.out.println(d.toPlainString()); // Printed 600 for me

I'm not into JSF (yet), but converter might look like this:

@FacesConverter("bigDecimalPlainDisplay")
public class BigDecimalDisplayConverter implements Converter {
    @Override
    public Object getAsObject(FacesContext context, UIComponent component, String value) {
        throw new BigDecimal(value);
    }

    @Override
    public String getAsString(FacesContext context, UIComponent component, Object value) {
        BigDecimal  bd = (BigDecimal)value;
        return bd.setScale(2, RoundingMode.HALF_UP).stripTrailingZeros().toPlainString();
    }
}

and then in xhtml:

<h:inputText id="bigDecimalView" value="#{bigDecimalObject}" 
    size="20" required="true" label="Value">
    <f:converter converterId="bigDecimalPlainDisplay" />
</h:inputText>

Answer 6

You can use DecimalFormat. For example:

BigDecimal value = new BigDecimal("15.3456").setScale(2, BigDecimal.ROUND_HALF_UP));
String valueString = new DecimalFormat("#.##").format(value);
System.out.println(valueString); //15.35

Please try yourself.