Parse ifconfig to get only my IP address using Bash

Question

I want to edit the bashrc file to have a simple function called \"myip\" to run. As you might guess, the function myip prints only my internal IP address of my machine.

Answer 1

IPv4 Examples using BASH4+

Example 1, using hostname:

  hostname -I|cut -d" " -f 1

Example 2, the device is known (and it never changes) :

  ifconfig ens5 | grep "inet" | awk '{print $2}' |  sed 's/[^0-9.]*//g'

Example 3, don't now the device (e.g. eth0, eth1, enp0s23, or wpxxx) :

 ip a | awk 'BEGIN{ "hostname -I|cut -d\" \" -f 1" | getline ip} $2 ~ ip {print "Device: "$NF "  IP: "$2}'

Example 4, want the network IP address:

 wget -q -O /dev/stdout http://checkip.dyndns.org/ | cut -d":" -f2 | cut -d \< -f1

enjoy.

Answer 2

This works for me:
ifconfig eth0 | awk '/inet addr/{print substr($2,6)}'