In Java, how to find if first character in a string is upper case without regex

Question

In Java, find if the first character in a string is upper case without using regular expressions.

Answer 1

Assuming s is non-empty:

Character.isUpperCase(s.charAt(0))

or, as mentioned by divec, to make it work for characters with code points above U+FFFF:

Character.isUpperCase(s.codePointAt(0));

Answer 2

we can find upper case letter by using regular expression as well

private static void findUppercaseFirstLetterInString(String content) {
    Matcher m = Pattern
            .compile("([a-z])([a-z]*)", Pattern.CASE_INSENSITIVE).matcher(
                    content);
    System.out.println("Given input string : " + content);
    while (m.find()) {
        if (m.group(1).equals(m.group(1).toUpperCase())) {
            System.out.println("First Letter Upper case match found :"
                    + m.group());
        }
    }
}

for detailed example . please visit http://www.onlinecodegeek.com/2015/09/how-to-determines-if-string-starts-with.html