Printing reverse of any String without using any predefined function?

Question

How to print the reverse of the String java is object orientated language without using any predefined function like reverse()?

Answer 1

ReverseString.java

public class ReverseString {
    public static void main(String[] args) {
        String str = "Ranga Reddy";
        String revStr = reverseStr(str);
        System.out.println(revStr);     
    }

    // Way1 - Recursive
    public static String reverseStr(String str) {
        char arrStr[] = reverseString(0, str.toCharArray());
        return new String(arrStr);
    }

    private static char[] reverseString(int charIndex, char[] arr) {     
        if (charIndex > arr.length - (charIndex+1)) {
          return arr;
        }

        int startIndex = charIndex;
        int endIndex = arr.length - (charIndex+1);

        char temp = arr[startIndex];        
        arr[startIndex] = arr[endIndex];
        arr[endIndex] = temp;      
        charIndex++;       
        return reverseString(charIndex++, arr);
    }

    // Way2
    private static String strReverse(String str) {
        char ch[] = new char[str.length()];
        for (int i = str.length() - 1, j = 0; i >= 0; i--) {
            ch[j++] = str.charAt(i);
        }
        return new String(ch);
    }
}

Answer 2

It is very simple using while loop

public class Test {
public static void main(String[] args) {
    String name = "subha chandra";
    int len = name.length();
    while(len > 0){
        len--;
        char c = name.charAt(len);
        System.out.print(c); // use String.valueOf(c) to convert char to String
    }
}    
}

Answer 3

final String s = "123456789";
final char[] word = s.toCharArray();
final int l = s.length() - 2;
final int ll = s.length() - 1;
for (int i = 0; i < l; i++) {
    char x = word[i];
    word[i] = word[ll - i];
    word[ll - i] = x;
}
System.out.println(s);
System.out.println(new String(word));

---

You can do it either recursively or iteratively (looping).

Iteratively:

static String reverseMe(String s) {
    StringBuilder sb = new StringBuilder();
    for (int i = s.length() - 1; i >= 0; --i)
        sb.append(s.charAt(i));
    return sb.toString();
}

Recursively:

static String reverseMe(String s) {
    if (s.length() == 0)
        return "";
    return s.charAt(s.length() - 1) + reverseMe(s.substring(1));
}

---

Integer i = new Integer(15);
test(i);
System.out.println(i);
test(i);
System.out.println(i); 
public static void test (Integer i) {
    i = (Integer)i + 10;
}

Answer 4

String a="Siva";

for(int i=0;i<=a.length()-1;i++){
    System.out.print(a.charAt(i));
}

for(int i = a.length() - 1; i >= 0; --i){
    System.out.println(a.charAt(i)); 
}

Answer 5

private void rev() {
    String st="hello";
    String b="";

    for(int i=st.length()-1;i>=0;i--){
        b=b+st.charAt(i);
    }

    System.out.println("reverse:::"+b);
}

Answer 6

public class ReverseString {

public static void main(String [] args) {

    String s = "reverse string" ;
    String b = "";

            for (int i = 0; i < s.length(); i++ ){
                 b= b + s.substring(s.length()-1-i, s.length()-i);

                 }

             System.out.println(b);
}