I am trying to draw a dendrogram from the hclust
function output. I hope the dendrogram is horizontally arranged instead of the default, which can be obtain by
To show your defined labels in horizontal dendrogram, one solution is to set row names of data frame to new labels (all labels should be unique).
require(graphics)
labs = paste("sta_",1:50,sep="") #new labels
USArrests2<-USArrests #new data frame (just to keep original unchanged)
rownames(USArrests2)<-labs #set new row names
hc <- hclust(dist(USArrests2), "ave")
par(mar=c(3,1,1,5))
plot(as.dendrogram(hc),horiz=T)
labs = paste("sta_",1:50,sep="") #new labels
rownames(USArrests)<-labs #set new row names
hc <- hclust(dist(USArrests), "ave")
library(ggplot2)
library(ggdendro)
#convert cluster object to use with ggplot
dendr <- dendro_data(hc, type="rectangle")
#your own labels (now rownames) are supplied in geom_text() and label=label
ggplot() +
geom_segment(data=segment(dendr), aes(x=x, y=y, xend=xend, yend=yend)) +
geom_text(data=label(dendr), aes(x=x, y=y, label=label, hjust=0), size=3) +
coord_flip() + scale_y_reverse(expand=c(0.2, 0)) +
theme(axis.line.y=element_blank(),
axis.ticks.y=element_blank(),
axis.text.y=element_blank(),
axis.title.y=element_blank(),
panel.background=element_rect(fill="white"),
panel.grid=element_blank())
Using dendrapply
you can customize your dendro as you like.
colLab <- function(n) {
if(is.leaf(n)) {
a <- attributes(n)
attr(n, "label") <- substr(a$label,1,2) # change the node label
attr(n, "nodePar") <- c(a$nodePar, lab.col = 'red') # change the node color
}
n
}
require(graphics)
hc <- hclust(dist(USArrests), "ave")
clusDendro <- as.dendrogram(hc)
clusDendro <- dendrapply(clusDendro, colLab)
op <- par(mar = par("mar") + c(0,0,0,2))
plot(clusDendro,horiz=T)