rbind multiple data sets [duplicate]

Answer 1

You can use do.call, like so:

do.call("rbind", list(DF1, DF2, DF3))

Note that second argument of do.call is a list.

Answer 2

This may help you:

You can use rbind.fill from plyr package (can be used even if column name is not the same)

Here is the example from dataset in optmatch package in R

library(optmatch)
 library(plyr)
data(nuclearplants)
x<-nuclearplants
data1<-as.data.frame(x$cost)
data1<-data1[1:20,]
data1<-as.data.frame(data1)
data2<-as.data.frame(x$date)
rbind.fill(data1,data2)

data1    x$date
1  460.05     NA
2  452.99     NA
3  443.22     NA
4  652.32     NA
5  642.23     NA
6  345.39     NA
7  272.37     NA
8  317.21     NA
9  457.12     NA
10 690.19     NA
11 350.63     NA
12 402.59     NA
13 412.18     NA
14 495.58     NA
15 394.36     NA
16 423.32     NA
17 712.27     NA
18 289.66     NA
19 881.24     NA
20 490.88     NA
21     NA  68.58
22     NA  67.33
23     NA  67.33
24     NA  68.00
25     NA  68.00
26     NA  67.92
27     NA  68.17
28     NA  68.42
29     NA  68.42
30     NA  68.33
31     NA  68.58
32     NA  68.75
33     NA  68.42
34     NA  68.92
35     NA  68.92
36     NA  68.42
37     NA  69.50
38     NA  68.42
39     NA  69.17
40     NA  68.92
41     NA  68.75
42     NA  70.92
43     NA  69.67
44     NA  70.08
45     NA  70.42
46     NA  71.08
47     NA  67.25
48     NA  67.17
49     NA  67.83
50     NA  67.83
51     NA  67.25
52     NA  67.83

Answer 3

For performance gains try rbindlist from the data.table package eg.

rbindlist(list(DF1,DF2,DF3))

Answer 4

The tidyverse approach is to use bind_rows() from the dplyr package:

bind_rows(DF1, DF2, DF3)