How to include forward slash in vi search & replace

Question

I have a file that contains the string usrbin. I want to search for usrbin and replace it with /usr/bin/.

I tried :%s/us

Answer 1

Here are two ways:

• escape the / which is the default substitute separator: :s/usrbin/\/usr\/bin
• use another substitute separator, e.g., using the hash # character: :s#usrbin#/usr/bin. Note that there are characters that you can't use as a separator: ", \, |