How to convert a time string to seconds?

Question

I need to convert time value strings given in the following format to seconds, for example:

1.\'00:00:00,000\' -> 0 seconds

2.\'00:00:10,000\' -> 10 s         


        

Answer 1

For Python 2.7:

>>> import datetime
>>> import time
>>> x = time.strptime('00:01:00,000'.split(',')[0],'%H:%M:%S')
>>> datetime.timedelta(hours=x.tm_hour,minutes=x.tm_min,seconds=x.tm_sec).total_seconds()
60.0

Answer 2

def time_to_sec(time):
    sep = ','
    rest = time.split(sep, 1)[0]
    splitted = rest.split(":")
    emel = len(splitted) - 1
    i = 0
    summa = 0
    for numb in splitted:
        szor = 60 ** (emel - i)
        i += 1
        summa += int(numb) * szor
    return summa

Answer 3

To get the timedelta(), you should subtract 1900-01-01:

>>> from datetime import datetime
>>> datetime.strptime('01:01:09,000', '%H:%M:%S,%f')
datetime.datetime(1900, 1, 1, 1, 1, 9)
>>> td = datetime.strptime('01:01:09,000', '%H:%M:%S,%f') - datetime(1900,1,1)
>>> td
datetime.timedelta(0, 3669)
>>> td.total_seconds() # 2.7+
3669.0

%H above implies the input is less than a day, to support the time difference more than a day:

>>> import re
>>> from datetime import timedelta
>>> td = timedelta(**dict(zip("hours minutes seconds milliseconds".split(),
...                           map(int, re.findall('\d+', '31:01:09,000')))))
>>> td
datetime.timedelta(1, 25269)
>>> td.total_seconds()
111669.0

To emulate .total_seconds() on Python 2.6:

>>> from __future__ import division
>>> ((td.days * 86400 + td.seconds) * 10**6 + td.microseconds) / 10**6
111669.0