I have setOnCheckedChangeListener
implemented for my checkbox
Is there a way I can call
checkbox.setChecked(false);
I guess using reflection is the only way. Something like this:
CheckBox cb = (CheckBox) findViewById(R.id.checkBox1);
try {
Field field = CompoundButton.class.getDeclaredField("mChecked");
field.setAccessible(true);
field.set(cb, cb.isChecked());
cb.refreshDrawableState();
cb.invalidate();
} catch (Exception e) {
e.printStackTrace();
}
You could use this SafeCheckBox class as your checkbox :
public class SafeCheckBox extends AppCompatCheckBox implements CompoundButton.OnCheckedChangeListener {
private OnSafeCheckedListener onSafeCheckedListener;
private int mIgnoreListener = CALL_LISTENER;
public static final int IGNORE = 0;
public static final int CALL_LISTENER = 1;
@Retention(RetentionPolicy.SOURCE)
@IntDef({IGNORE, CALL_LISTENER})
public @interface ListenerMode {
}
public SafeCheckBox(Context context) {
super(context);
init(context);
}
public SafeCheckBox(Context context, AttributeSet attrs) {
super(context, attrs);
init(context);
}
public SafeCheckBox(Context context, AttributeSet attrs, int defStyleAttr) {
super(context, attrs, defStyleAttr);
init(context);
}
/**
* @param checkState change state of the checkbox to
* @param mIgnoreListener true to ignore the listener else listener will be notified
*/
public void setSafeCheck(boolean checkState, @ListenerMode int mIgnoreListener) {
if (isChecked() == checkState) return; //already in the same state no need to fire listener.
if (onSafeCheckedListener != null) { // this to avoid a bug if the user listens for the event after using this method and in that case he will miss first check
this.mIgnoreListener = mIgnoreListener;
} else {
this.mIgnoreListener = CALL_LISTENER;
}
setChecked(checkState);
}
private void init(Context context) {
setOnCheckedChangeListener(this);
}
public OnSafeCheckedListener getOnSafeCheckedListener() {
return onSafeCheckedListener;
}
public void setOnSafeCheckedListener(OnSafeCheckedListener onSafeCheckedListener) {
this.onSafeCheckedListener = onSafeCheckedListener;
}
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if (onSafeCheckedListener != null)
onSafeCheckedListener.onAlwaysCalledListener(buttonView, isChecked);// this has to be called before onCheckedChange
if (onSafeCheckedListener != null && (mIgnoreListener == CALL_LISTENER)) {
onSafeCheckedListener.onCheckedChanged(buttonView, isChecked);
}
mIgnoreListener = CALL_LISTENER;
}
/**
* Listener that will be called when you want it to be called.
* On checked change listeners are called even when the setElementChecked is called from code. :(
*/
public interface OnSafeCheckedListener extends OnCheckedChangeListener {
void onAlwaysCalledListener(CompoundButton buttonView, boolean isChecked);
}
}
Then you could call :-
setSafeCheck(true,ListenerMode.IGNORE);// OnCheckedChange listener will not be notified
No, you can't do it. The onCheckedChanged
method is called directly from setChecked
. What you can do is the following:
mCheck.setOnCheckedChangeListener (null);
mCheck.setChecked (false);
mCheck.setOnCheckedChangeListener (mListener);
See the source of CheckBox, and the implementation of setChecked
:
public void setChecked(boolean checked) {
if (mChecked != checked) {
mChecked = checked;
refreshDrawableState();
// Avoid infinite recursions if setChecked() is called from a listener
if (mBroadcasting) {
return;
}
mBroadcasting = true;
if (mOnCheckedChangeListener != null) {
mOnCheckedChangeListener.onCheckedChanged(this, mChecked);
}
if (mOnCheckedChangeWidgetListener != null) {
mOnCheckedChangeWidgetListener.onCheckedChanged(this, mChecked);
}
mBroadcasting = false;
}
}
Another possible way to achieve this is by using a custom CheckBox , which will let you choose if you want the listener to be called or not :
public class CheckBox extends AppCompatCheckBox {
private OnCheckedChangeListener mListener;
public CheckBox(final Context context) {
super(context);
}
public CheckBox(final Context context, final AttributeSet attrs) {
super(context, attrs);
}
public CheckBox(final Context context, final AttributeSet attrs, final int defStyleAttr) {
super(context, attrs, defStyleAttr);
}
@Override
public void setOnCheckedChangeListener(final OnCheckedChangeListener listener) {
mListener = listener;
super.setOnCheckedChangeListener(listener);
}
public void setChecked(final boolean checked, final boolean alsoNotify) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null);
super.setChecked(checked);
super.setOnCheckedChangeListener(mListener);
return;
}
super.setChecked(checked);
}
public void toggle(boolean alsoNotify) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null);
super.toggle();
super.setOnCheckedChangeListener(mListener);
}
super.toggle();
}
}
Kotlin version, if you prefer:
class CheckBox @JvmOverloads constructor(context: Context, attrs: AttributeSet? = null, defStyleAttr: Int = 0) : AppCompatCheckBox(context, attrs, defStyleAttr) {
private var listener: CompoundButton.OnCheckedChangeListener? = null
override fun setOnCheckedChangeListener(listener: CompoundButton.OnCheckedChangeListener?) {
this.listener = listener
super.setOnCheckedChangeListener(listener)
}
fun setChecked(checked: Boolean, alsoNotify: Boolean) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null)
super.setChecked(checked)
super.setOnCheckedChangeListener(listener)
return
}
super.setChecked(checked)
}
fun toggle(alsoNotify: Boolean) {
if (!alsoNotify) {
super.setOnCheckedChangeListener(null)
super.toggle()
super.setOnCheckedChangeListener(listener)
}
super.toggle()
}
}
sample usage:
checkBox.setChecked(true,false);
How about this. Try to use Tag in View
mCheck.setTag("ignore");
mCheck.setChecked(true);
mCheck.setTag(null);
and
switch.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean selected) {
//If switch has a tag, ignore below
if(compoundButton.getTag() != null)
return;
if (selected) {
// do something
} else {
// do something else
}
}
});
My solution written in java based on @Chris answer:
chkParent.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if(buttonView.getTag() != null){
buttonView.setTag(null);
return;
}
if(isChecked){
chkChild.setTag(true);
chkChild.setChecked(false);
}
else{
chkParent.setChecked(true);
}
}
});
chkChild.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
if(buttonView.getTag() != null){
buttonView.setTag(null);
return;
}
if(isChecked){
chkParent.setTag(true);
chkParent.setChecked(false);
}
else{
chkChild.setChecked(true);
}
}
});
2 checkboxes and always one will be checked (one be must checked initially though). Setting tag to true blocks onCheckedChanged listener.