I want to turn an R data.frame into a JSON object in order to use it for preparing data visualizations with d3.js. I found a lot of questions that asked how to get JSON into
This is a recursive approach which is cleaner:
require(RJSONIO)
makeList<-function(x){
if(ncol(x)>2){
listSplit<-split(x[-1],x[1],drop=T)
lapply(names(listSplit),function(y){list(name=y,children=makeList(listSplit[[y]]))})
}else{
lapply(seq(nrow(x[1])),function(y){list(name=x[,1][y],Percentage=x[,2][y])})
}
}
jsonOut<-toJSON(list(name="MyData",children=makeList(MyData[-1])))
cat(jsonOut)
Using a combination of split
and subset
may get what you want. For example
library(RJSONIO)
list1<-split(subset(MyData,select=c(-Location)),Mydata$Location)
list2<-lapply(list1,function(x){split(subset(x,select=c(-Station)),x$Station,drop=TRUE)})
list3<-lapply(list2,function(x){lapply(x,function(y){split(subset(y,select=c(-Size,-ID)),y$Size,drop=TRUE)})})
jsonOut<-toJSON(list(MyData=list3))
jsonOut1<-gsub('([^\n]*?): \\{\n "Percentage"','\\{"name":\\1,"Percentage"',jsonOut)
jsonOut2<-gsub('"([^"]*?)": \\{','"name":"\\1","children":\\{',jsonOut1)
cat(jsonOut2)
{
"name":"MyData","children":{
"name":"Alpha","children":{
"name":"Yota","children":{
{"name": "Big","Percentage": 0.85
},
{"name":"Medium","Percentage": 0.19
},
{"name":"small","Percentage": 0.89
}
},
"name":"Zeta","children":{
{"name": "Big","Percentage": 0.63
},
{"name":"Medium","Percentage": 0.43
},
{"name":"small","Percentage": 0.47
}
}
},
"name":"Beta","children":{
"name":"Meta","children":{
{"name": "Big","Percentage": 0.89
},
{"name":"Medium","Percentage": 0.71
},
{"name":"small","Percentage": 0.59
}
},
"name":"Theta","children":{
{"name": "Big","Percentage": 0.09
},
{"name":"Medium","Percentage": 0.33
},
{"name":"small","Percentage": 0.79
}
}
}
}
}
I am pigging backing off of user1609452's answer and answering the question about non regular file hierarchies. If you have a column where some data have children and some do not, use the following:
makeList<-function(x){
if(ncol(x)>2){
listSplit<-split(x[-1],x[1],drop=T)
lapply(names(listSplit),function(y){
if(as.character(listSplit[[y]][1,1]) > 0){
list(name=y,children=makeList(listSplit[[y]]))
} else {
list(name=y,size=listSplit[[y]][1,2])
}
})
}else{
lapply(seq(nrow(x[1])),function(y){list(name=x[,1][y],size=x[,2][y])})
}
}
Basically we check if the current row has more children or if it simply needs to have size appended to it.