javascript regex for special characters

Question

I\'m trying to create a validation for a password field which allows only the a-zA-Z0-9 characters and .!@#$%^&*()_+-=

I can\'t seem to

Answer 1

// Regex for special symbols

var regex_symbols= /[-!$%^&*()_+|~=`{}\[\]:\/;<>?,.@#]/;

Answer 2

How about this:-

var regularExpression = /^(?=.*[0-9])(?=.*[!@#$%^&*])[a-zA-Z0-9!@#$%^&*]{6,}$/;

It will allow a minimum of 6 characters including numbers, alphabets, and special characters

Answer 3

var regex = /^[a-zA-Z0-9!@#\$%\^\&*\)\(+=._-]+$/g

Should work

Also may want to have a minimum length i.e. 6 characters

var regex = /^[a-zA-Z0-9!@#\$%\^\&*\)\(+=._-]{6,}$/g

Answer 4

You can be specific by testing for not valid characters. This will return true for anything not alphanumeric and space:

var specials = /[^A-Za-z 0-9]/g;
return specials.test(input.val());

Answer 5

There are some issue with above written Regex.

This works perfectly.

^[a-zA-Z\d\-_.,\s]+$

Only allowed special characters are included here and can be extended after comma.

Answer 6

This regex works well for me to validate password:

/[ !"#$%&'()*+,-./:;<=>?@[\\\]^_`{|}~]/

This list of special characters (including white space and punctuation) was taken from here: https://www.owasp.org/index.php/Password_special_characters. It was changed a bit, cause backslash ('\') and closing bracket (']') had to be escaped for proper work of the regex. That's why two additional backslash characters were added.