How to convert an H:MM:SS time string to seconds in Python?

Question

Basically I have the inverse of this problem: Python Time Seconds to h:m:s

I have a string in the format H:MM:SS (always 2 digits for minutes and seconds), and I nee

Answer 1

Using datetime module

import datetime
t = '10:15:30'
h,m,s = t.split(':')
print(int(datetime.timedelta(hours=int(h),minutes=int(m),seconds=int(s)).total_seconds()))

Output: 36930

Answer 2

parts = time_string.split(":")
seconds = int(parts[0])*(60*60) + int(parts[1])*60 + int(parts[2])

Answer 3

I didn't really like any of the given answers, so I used the following:

def timestamp_to_seconds(t):
    return sum(float(n) * m for n,
               m in zip(reversed(time.split(':')), (1, 60, 3600))
               )

Answer 4

ts = '1:23:45'
secs = sum(int(x) * 60 ** i for i, x in enumerate(reversed(ts.split(':'))))
print(secs)

Answer 5

Expanding on @FMc's solution which embodies half of Horner's method. Advantage of Horner's method: Skip reversing the list, avoid power calculation.

from functools import reduce

timestamp = "1:23:45"
reduce(lambda sum, d: sum * 60 + int(d), timestamp.split(":"), 0)

Answer 6

Another alternative if you have days on string:

def duration2sec(string):
    if "days" in string:
        days = string.split()[0]
        hours = string.split()[2].split(':')
        return int(days) * 86400 + int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])
    else:
        hours = string.split(':')
        return int(hours[0]) * 3600 + int(hours[1]) * 60 + int(hours[2])