How to preserve line breaks when storing command output to a variable?

Question

I’m using bash shell on Linux. I have this simple script …

#!/bin/bash

TEMP=`sed -n \'/\'\"Starting deployment of\"\'/,/\'\"Failed to start context\"\'/p\'         


        

Answer 1

I have ran into the same problem, a quote will help

ubuntu@host:~/apps$ apps="abc
> def"
ubuntu@host:~/apps$ echo $apps
abc def
ubuntu@host:~/apps$ echo "$apps"
abc
def

Answer 2

Quote your variables. Here is it why:

$ f="fafafda
> adffd
> adfadf
> adfafd
> afd"

$ echo $f
fafafda adffd adfadf adfafd afd

$ echo "$f"
fafafda
adffd
adfadf
adfafd
afd

Without quotes, the shell replaces $TEMP with the characters it contains (one of which is a newline). Then, before invoking echo shell splits that string into multiple arguments using the Internal Field Separator (IFS), and passes that resulting list of arguments to echo. By default, the IFS is set to whitespace (spaces, tabs, and newlines), so the shell chops your $TEMP string into arguments and it never gets to see the newline, because the shell considers it a separator, just like a space.