How to make iPhone vibrate using Swift?

Question

I need to make the iPhone vibrate, but I don\'t know how to do that in Swift. I know that in Objective-C, you just write:

import AudioToolbox
AudioServicesPl         


        

Answer 1

Swift 4.2, 5.0

 if #available(iOS 10.0, *) {
      UIImpactFeedbackGenerator(style: .light).impactOccurred()
   } 

You can also choose other styles like

    style: .heavy
    style: .medium

    //Note: soft and rigid available in only iOS 13.0
    style: .soft
    style: .rigid

Answer 2

For iOS 10.0+ You can try UIFeedbackGenerator

Simple viewController above, just replace your view controller in your test "single view app"

import UIKit

class ViewController: UIViewController {

    var i = 0

    override func viewDidLoad() {
        super.viewDidLoad()

        let btn = UIButton()
        self.view.addSubview(btn)
        btn.translatesAutoresizingMaskIntoConstraints = false

        btn.widthAnchor.constraint(equalToConstant: 160).isActive = true
        btn.heightAnchor.constraint(equalToConstant: 160).isActive = true
        btn.centerXAnchor.constraint(equalTo: view.centerXAnchor).isActive = true
        btn.centerYAnchor.constraint(equalTo: view.centerYAnchor).isActive = true

        btn.setTitle("Tap me!", for: .normal)
        btn.setTitleColor(UIColor.red, for: .normal)
        btn.addTarget(self, action: #selector(tapped), for: .touchUpInside)
    }

    @objc func tapped() {
        i += 1
        print("Running \(i)")

        switch i {
        case 1:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.error)

        case 2:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.success)

        case 3:
            let generator = UINotificationFeedbackGenerator()
            generator.notificationOccurred(.warning)

        case 4:
            let generator = UIImpactFeedbackGenerator(style: .light)
            generator.impactOccurred()
        case 5:
            let generator = UIImpactFeedbackGenerator(style: .medium)
            generator.impactOccurred()

        case 6:
            let generator = UIImpactFeedbackGenerator(style: .heavy)
            generator.impactOccurred()

        default:
            let generator = UISelectionFeedbackGenerator()
            generator.selectionChanged()
            i = 0
        }
    }
}

Answer 3

We can do this in Xcode7.1

import UIKit
import AudioToolbox


class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()

        AudioServicesPlayAlertSound(kSystemSoundID_Vibrate)
    }
}

Answer 4

Short example:

import UIKit
import AudioToolbox

class ViewController: UIViewController {

    override func viewDidLoad() {
        super.viewDidLoad()
        AudioServicesPlayAlertSound(SystemSoundID(kSystemSoundID_Vibrate))            
    }
}

load onto your phone and it will vibrate. You can put it in a function or IBAction as you wish.

Code Update:

 AudioServicesPlayAlertSoundWithCompletion(SystemSoundID(kSystemSoundID_Vibrate)) { }

As apple code docs written:

This function will be deprecated in a future release. Use AudioServicesPlaySystemSoundWithCompletion instead.

NOTE: If vibrate doesn't work. check vibrate is enable in sounds and haptics settings

Answer 5

You can vibrate the phone using either AudioServices or Haptic Feedback.

// AudioServices
AudioServicesPlayAlertSound(SystemSoundID(kSystemSoundID_Vibrate))

// Haptic Feedback
UIImpactFeedbackGenerator(style: .medium).impactOccurred()

Checkout my open source framework Haptica, it supports both Haptic Feedback, AudioServices and unique vibrations patterns. Works on Swift 4.2, Xcode 10