I\'m searching a directory recursively using grep with the following arguments hoping to only return the first match. Unfortunately, it returns more than one -- in-fact two
My grep-a-like program ack has a -1
option that stops at the first match found anywhere. It supports the -m 1
that @mvp refers to as well. I put it in there because if I'm searching a big tree of source code to find something that I know exists in only one file, it's unnecessary to find it and have to hit Ctrl-C.
You can use below command if you want to print entire line and file name if the occurrence of particular word in current directory you are searching.
grep -m 1 -r "Not caching" * | head -1
-m 1
means return the first match in any given file. But it will still continue to search in other files. Also, if there are two or more matched in the same line, all of them will be displayed.
head -1
to solve this problem:grep -o -a -m 1 -h -r "Pulsanti Operietur" /path/to/dir | head -1
-o, --only-matching, print only the matched part of the line (instead of the entire line)
-a, --text, process a binary file as if it were text
-m 1, --max-count, stop reading a file after 1 matching line
-h, --no-filename, suppress the prefixing of file names on output
-r, --recursive, read all files under a directory recursively
You can pipe grep
result to head
in conjunction with stdbuf.
Note, that in order to ensure stopping after Nth match, you need to using stdbuf
to make sure grep
don't buffer its output:
stdbuf -oL grep -rl 'pattern' * | head -n1
stdbuf -oL grep -o -a -m 1 -h -r "Pulsanti Operietur" /path/to/dir | head -n1
stdbuf -oL grep -nH -m 1 -R "django.conf.urls.defaults" * | head -n1
As soon as head
consumes 1 line, it terminated and grep
will receive SIGPIPE
because it still output something to pipe while head
was gone.
This assumed that no file names contain newline.
A single liner, using find
:
find -type f -exec grep -lm1 "PATTERN" {} \; -a -quit