Linux command to list all available commands and aliases

Question

Is there a Linux command that will list all available commands and aliases for this terminal session?

As if you typed \'a\' and pressed tab, but for every letter of

Answer 1

Here's a function you can put in your bashrc file:

function command-search
{
   oldIFS=${IFS}
   IFS=":"

   for p in ${PATH}
   do
      ls $p | grep $1
   done

   export IFS=${oldIFS}
}

Example usage:

$ command-search gnome
gnome-audio-profiles-properties*
gnome-eject@
gnome-keyring*
gnome-keyring-daemon*
gnome-mount*
gnome-open*
gnome-sound-recorder*
gnome-text-editor@
gnome-umount@
gnome-volume-control*
polkit-gnome-authorization*
vim.gnome*
$

FYI: IFS is a variable that bash uses to split strings.

Certainly there could be some better ways to do this.

Answer 2

in debian: ls /bin/ | grep "whatImSearchingFor"

Answer 3

compgen -c > list.txt && wc list.txt

Answer 4

You can always to the following:

1. Hold the $PATH environment variable value.
2. Split by ":"
3. For earch entry: 
    ls * $entry 
4. grep your command in that output.

The shell will execute command only if they are listed in the path env var anyway.

Answer 5

Why don't you just type:

seachstr

In the terminal.

The shell will say somehing like

seacrhstr: command not found 

EDIT:

Ok, I take the downvote, because the answer is stupid, I just want to know: What's wrong with this answer!!! The asker said:

and see if a command is available.

Typing the command will tell you if it is available!.

Probably he/she meant "with out executing the command" or "to include it in a script" but I cannot read his mind ( is not that I can't regularly it is just that he's wearing a mind reading deflector )

Answer 6

For Mac users (find doesn't have -executable and xargs doesn't have -d):

echo $PATH | tr ':' '\n' | xargs -I {} find {} -maxdepth 1 -type f -perm '++x'